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klemol [59]
2 years ago
11

What’s the answer to this question

Mathematics
1 answer:
cricket20 [7]2 years ago
6 0

Answer:

398 * 1.034^t

Step-by-step explanation:

P = 398(1 + 3.4%)^t = 398 * 1.034^t

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Find the value of the following expression 100 - 2(x + 5) when x = 10 *
Ede4ka [16]

Answer:

70

Step-by-step explanation:

100 - 2(x + 5) = 100 - 2x - 10 = 90 -2x

90 - 2x

90 - 2×10

90 - 20 = 70

4 0
2 years ago
Read 2 more answers
Which are correct representations of the inequality -3(2x - 5) <5(2-x)? Select two options.
antoniya [11.8K]

Answer:

what? I don't get

Step-by-step explanation:

4 0
3 years ago
In the Isoceles triangle, the legs
aalyn [17]

Check the picture below.

since we know that x = 3/7, we can then plug that on either of the twin legs, since it's an isosceles, and get the length of each leg, so say let's plug it in 5x + 16

5x + 16\implies 5\left( \cfrac{3}{7} \right)+16\implies \cfrac{38}{7}+16\implies \cfrac{38+112}{7}\implies \cfrac{150}{7}\\\\[-0.35em]\rule{34em}{0.25pt}\\\\\stackrel{\textit{both legs}}{\cfrac{150}{7}+\cfrac{150}{7}}+\stackrel{\textit{base}}{6}\implies \cfrac{150+150+42}{7}\implies \cfrac{342}{7}\implies 48\frac{6}{7}\impliedby \textit{perimeter}

3 0
3 years ago
6z-4-z+10=-9 plz help and hurry
Anna35 [415]
6z -4 - z + 10 = -9
Combine like terms
5z + 6 = -9
Subtract both sides by 6
5z = -15
Divide both sides by 5
z = -3
Have an awesome day! :)
7 0
2 years ago
2−2s=4/3 s+13 how do you do this
soldi70 [24.7K]

Answer: s = -3.3

<u>Step-by-step explanation:</u>

2-2s=\dfrac{4}{3}s+13\\\\\\\underline{\text{Multiply everything by 3 to clear the denominator:}}\\(3)2-(3)2s=(3)\dfrac{4}{3}s+(3)13\\\\.\qquad 6-6s=4s+39\\\\\\\underline{\text{Add 6s to both sides:}}\\.\qquad 6-6s+6s=4s+6s+39\\\\.\qquad \qquad \qquad 6=10s+39\\\\\\\underline{\text{Subtract 39 from both sides:}}\\.\qquad \qquad 6-39=10s+39-39\\\\.\qquad \quad \quad -33=10s\\\\\\\underline{\text{Divide both sides by 10:}}\\.\qquad \quad \quad \dfrac{-33}{10}=\dfrac{10s}{10}

                -3.3 = s

3 0
2 years ago
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