The probability of getting a 1 on the first roll is 1/6.
The probability of getting a 6 on the second roll is also 1/6.
The percent decrease in people going to the movies from Saturday to Sunday is 35.3%
Step-by-step explanation:
The percent decrease is given by the formula:
![Percent\ decrease = \frac{Decrease}{Old\ Value}*100\\where \\Decrease = Old\ value -New\ value\\](https://tex.z-dn.net/?f=Percent%5C%20decrease%20%3D%20%5Cfrac%7BDecrease%7D%7BOld%5C%20Value%7D%2A100%5C%5Cwhere%20%5C%5CDecrease%20%3D%20Old%5C%20value%20-New%5C%20value%5C%5C)
Given
New Value = 956
Old Value = 1478
Decrease = 1478-956
= 522
![Percent\ decrease= \frac{522}{1478}*100\\=0.353*100\\=35.3\%](https://tex.z-dn.net/?f=Percent%5C%20decrease%3D%20%5Cfrac%7B522%7D%7B1478%7D%2A100%5C%5C%3D0.353%2A100%5C%5C%3D35.3%5C%25)
The percent decrease in people going to the movies from Saturday to Sunday is 35.3%
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Considering the hang time equation, it is found that Player 1 jumped 0.68 feet higher than Player 2.
<h3>What is the hang time equation?</h3>
The hang-time of the ball for a player of jump h is given by:
![t = 2\left(\frac{2h}{32}\right)^{\frac{1}{2}}](https://tex.z-dn.net/?f=t%20%3D%202%5Cleft%28%5Cfrac%7B2h%7D%7B32%7D%5Cright%29%5E%7B%5Cfrac%7B1%7D%7B2%7D%7D)
The expression can be simplified as:
![t = 2\sqrt{\frac{h}{16}}](https://tex.z-dn.net/?f=t%20%3D%202%5Csqrt%7B%5Cfrac%7Bh%7D%7B16%7D%7D)
For a player that has a hang time of 0.9s, the jump is found as follows:
![0.9 = 2\sqrt{\frac{h}{16}}](https://tex.z-dn.net/?f=0.9%20%3D%202%5Csqrt%7B%5Cfrac%7Bh%7D%7B16%7D%7D)
![\sqrt{\frac{h}{16}} = \frac{0.9}{2}](https://tex.z-dn.net/?f=%5Csqrt%7B%5Cfrac%7Bh%7D%7B16%7D%7D%20%3D%20%5Cfrac%7B0.9%7D%7B2%7D)
![(\sqrt{\frac{h}{16}})^2 = \left(\frac{0.9}{2}\right)^2](https://tex.z-dn.net/?f=%28%5Csqrt%7B%5Cfrac%7Bh%7D%7B16%7D%7D%29%5E2%20%3D%20%5Cleft%28%5Cfrac%7B0.9%7D%7B2%7D%5Cright%29%5E2)
![h = 16\left(\frac{0.9}{2}\right)^2](https://tex.z-dn.net/?f=h%20%3D%2016%5Cleft%28%5Cfrac%7B0.9%7D%7B2%7D%5Cright%29%5E2)
h = 3.24 feet.
For a player that has a hang time of 0.8s, the jump is found as follows:
![0.8 = 2\sqrt{\frac{h}{16}}](https://tex.z-dn.net/?f=0.8%20%3D%202%5Csqrt%7B%5Cfrac%7Bh%7D%7B16%7D%7D)
![\sqrt{\frac{h}{16}} = \frac{0.8}{2}](https://tex.z-dn.net/?f=%5Csqrt%7B%5Cfrac%7Bh%7D%7B16%7D%7D%20%3D%20%5Cfrac%7B0.8%7D%7B2%7D)
![(\sqrt{\frac{h}{16}})^2 = \left(\frac{0.8}{2}\right)^2](https://tex.z-dn.net/?f=%28%5Csqrt%7B%5Cfrac%7Bh%7D%7B16%7D%7D%29%5E2%20%3D%20%5Cleft%28%5Cfrac%7B0.8%7D%7B2%7D%5Cright%29%5E2)
![h = 16\left(\frac{0.8}{2}\right)^2](https://tex.z-dn.net/?f=h%20%3D%2016%5Cleft%28%5Cfrac%7B0.8%7D%7B2%7D%5Cright%29%5E2)
h = 2.56 feet.
The difference is given by:
3.24 - 2.56 = 0.68 feet.
More can be learned about equations at brainly.com/question/25537936
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B the answer is B
To create a survey you need a common entity linked to a unique feature
With B…he is able to create a table,draw a graph ,a pie chart and do so