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Anna71 [15]
2 years ago
6

PLSSSSS HELPPPPP 20 POINTSSS EASY MATHHHH How many of each different 2-D shapes do you see?

Mathematics
2 answers:
Natalka [10]2 years ago
5 0
I see 5
There’s 2 triangles, one parallelogram and 2 other triangle thingies
Hope this helps
sergiy2304 [10]2 years ago
4 0
I think there’s two triangles and 3 rectangles
You might be interested in
I need help please :(
mixer [17]

Answer:

x = 7

Step-by-step explanation:

Given:

∠DEF = 117°

∠DEG = (12x + 1)°

∠GEF = (5x - 3)°

Find:

value of x

Computation:

∠DEF = ∠DEG + ∠GEF

117° = (12x + 1)° + (5x - 3)°

117° = 17 x - 2

x = 7

7 0
2 years ago
Read 2 more answers
Question 7 of 10
yanalaym [24]
The answer is Subtraction
3 0
2 years ago
Multiply.<br><br> (3x+2)(2x−5)<br><br><br> 6x^2+4x−3<br> 6x^2−10<br> 6x^2−11x−10<br> 6x^2−13x−3
Serjik [45]

Answer: Heyaa! ^^

Your Answer when multiplied is.. 6x²−11x−10

Step-by-step explanation:

  • 6x^2−11x−10
  • Expand the polynomial using the FOIL method.

                    - FOIL EXPLANATION -

  • A handy way to remember how to multiply two binomials.

It stands for "First, Outer, Inner, Last"

  • - It is the sum of: -

· multiplying the First terms,

· multiplying the Outer terms,

· multiplying the Inner terms, and

· multiplying the Last terms

<em>Hopefully this helps you! ~</em>

6 0
2 years ago
The table below shows all outcomes for rolling 2 dice. The bold numbers 1 through 6 show the possible results for each die. All
Leokris [45]

Part I:

1. If you have to circle each outcome in the table that at least 1 die is a 4, then you have to circle row corresponding to the number 4 and column corresponding to the number 4.

2. If you have to cross out each outcome where the sum of the dice is greater than 5, then you have to cross out all not bold numbers 6, 7, 8, 9, 10, 11 and 12 in the table.

Part II:

Here you can see 36 possible outcomes.

1. The probability that at least 1 die is a 4 is:

Pr(A)=\dfrac{11}{36} - (favorable outcomes are 4+1=5, 4+2=6, 4+3=7, 4+4=8, 4+5=9, 4+6=10, 1+4=5, 2+4=6, 3+4=7, 5+4=9, 6+4=10).

2. The probability that the sum of the dice is greater than 5 is:

Pr(B)=\dfrac{26}{36}=\dfrac{13}{18}.

3. The probability that at least 1 die is a 4 and that the sum of the dice is greater than 5 is

Pr(A\cap B)=\dfrac{9}{36}=\dfrac{1}{4}.

4. The probability that at least 1 die is a 4 or that the sum of the dice is greater than 5 is:

Pr(A\cup B)=\dfrac{28}{36}=\dfrac{7}{9}.

4 0
3 years ago
Can someone pls help ​
Basile [38]

Answer:

15x - 2.

Step-by-step explanation:

3x - 1 + 2x + 1 + 4x - 2 + 4x - 4 + 2x + 4

= 15x - 2.

5 0
3 years ago
Read 2 more answers
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