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Musya8 [376]
2 years ago
14

Compare the two functions shown below. Select the two statements that are true ​

Mathematics
2 answers:
Ugo [173]2 years ago
8 0

Answer:

your answer is C

explanation:

your answer is C because when you look at function 1 you see what Y equals and then you look at function 2 you see what Y and X equals and on both of them they increase. They increase to me but I don’t know about other people

makvit [3.9K]2 years ago
7 0
The answer would be option C
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There are 10 cranberry and 15 strawberry juices. You randomly pick two juices. What's the probability you'll get two strawberry
lorasvet [3.4K]

Answer:

  • 7/20

Explanation:

The theoretical probability, P (A), of an event, A, is:

  • P(A) = number of outcomes of event A / total number of possible outcomes

For 10 cranberry and 15 strawberry juices, the number of outcomes for two strawberry juices are:

  • Combination of 15 strawberry juices chosen in two:

C^{15}_{2}=\frac{15!}{(15-2)!(2!)}=\frac{15!}{13!2!}=\frac{15\times 14}{2}=105

The total number of possible outcomes is:

  • Combination of 25 juices chosen in two:

C^{25}_{2}=\frac{25!}{(25-2)!(2!)}=\frac{25!}{23!2!}=\frac{25\times 24}{2}=300

Thus, the probability of randomly picking two strawberry juices is:

  • P (two strawberry juices) = 105/300 = 7/20

Note that you can obtain it as the product of the probabilities that the first juice is a strawberry juice and the second juice is also strawberry juice:

15/25\times 14/24=(15\times 25)/(14\times 24)=210/600=7/20

5 0
3 years ago
Help me..............................................................................
vovangra [49]
Answer: C. $7.50 per box.
7 0
3 years ago
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Divide. What is the remainder?<br><br> 845 ÷ 73<br><br> 42<br> 11<br> 31<br> 22
astra-53 [7]
The remainder to this question is 42
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Help me my shawtys<br> 6 − x = −12
galben [10]

Answer:

D.18

Step-by-step explanation:

6-x=-12

-x=-12-6

-x=-18   divide both sides by -1

x=18

3 0
2 years ago
30+ Points!!!<br> 5. Solve the following inequalities.<br> a) 2 log3x – 2 logx3 -3 &lt;0
Ilya [14]

Answer:

I answered your last question also

2 log3x – 2 logx3 -3 <0

\mathrm{Subtract\:}2\log ^3\left(x\right)\mathrm{\:from\:both\:sides}

2\log ^3\left(x\right)-2logx^3-3-2\log ^3\left(x\right)

\mathrm{Simplify}

-2logx^3-3

\mathrm{Add\:}3\mathrm{\:to\:both\:sides}

-2logx^3-3+3

\mathrm{Simplify}

-2logx^3

Multiply\:both\:sides\:by\:-1\:\left(reverse\:the\:inequality\right)

\left(-2logx^3\right)\left(-1\right)>-2\log ^3\left(x\right)\left(-1\right)+3\left(-1\right)

\mathrm{Simplify}

2lx^3og>2\log ^3\left(x\right)-3

\mathrm{Divide\:both\:sides\:by\:}2lx^3o;\quad \:l>0

\frac{2lx^3og}{2lx^3o}>\frac{2\log ^3\left(x\right)}{2lx^3o}-\frac{3}{2lx^3o};\quad \:l>0\\

\mathrm{Simplify}

g>\frac{2\log ^3\left(x\right)-3}{2lx^3o};\quad \:l>0

Step-by-step explanation:

6 0
3 years ago
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