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xenn [34]
3 years ago
10

Simplify : 3/4 (1/2x - 12) + 4/5

Mathematics
2 answers:
DedPeter [7]3 years ago
5 0
3x-41/8if you every have a promblem with math you can use math
way to help you solve the promblem and it also explain to you how to solve it.


Margarita [4]3 years ago
4 0

Answer:

3/4(1/2x-12+4/5

Step-by-step explanation:

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Tiana can afford $150 per month for a car payment. Her bank preapproved her for a 6% interest rate for 5 years. What is the maxi
Pavel [41]

5 YEARS SHE WILL PAY =150 *12 *5 =9000


ON THAT 6% IS INTEREST


VALUE OF THE CAR IS 100- 6 =94 % OF 9000


WHICH IS 9000*.94= 8460

4 0
3 years ago
(3 8) 1 = 3 (8 1) A.True B.False
Zepler [3.9K]
Hi there!

This is pretty easy if you remember PEMDAS.

P = Parenthesis, and that's all we have in our equation so we'll work out what's in the parenthesis first.

(3×8) = 24. Then we go to the outside of the parenthesis and multiply 24 by whatever is on the outside.
24×1 =, well, 24.

Now we can go to the other side.

(8×1) = 8
8×3 = 24

Wow! Wouldja look at that? We are left with

24 = 24

The correct answer is A) True.

Hope this helps! <3
3 0
3 years ago
Can someone please help me ?
Nataliya [291]

Answer:

both problems are proportional


8 0
3 years ago
Suppose a 90% confidence interval for the mean salary of college graduates in a town in Mississippi is given by [$38,737, $50,46
JulsSmile [24]

Answer:

a. The point estimate was of $44,600.

b. The sample size was of 16.

Step-by-step explanation:

Confidence interval concepts:

A confidence interval has two bounds, a lower bound and an upper bound.

A confidence interval is symmetric, which means that the point estimate used is the mid point between these two bounds, that is, the mean of the two bounds.

The margin of error is the difference between the two bounds, divided by 2.

a. What is the point estimate of the mean salary for all college graduates in this town?

Mean of the bounds, so:

(38737+50463)/2 = 44600.

The point estimate was of $44,600.

b. Determine the sample size used for the analysis.

First we need to find the margin of error, so:

M = \frac{50463-38737}{2} = 5863

Relating the margin of error with the sample size:

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1 - 0.9}{2} = 0.05

Now, we have to find z in the Z-table as such z has a p-value of 1 - \alpha.

That is z with a pvalue of 1 - 0.05 = 0.95, so Z = 1.64.

Now, find the margin of error M as such

M = z\frac{\sigma}{\sqrt{n}}

In which \sigma is the standard deviation of the population and n is the size of the sample.

For this problem, we have that \sigma = 14300, M = 5863. So

M = z\frac{\sigma}{\sqrt{n}}

5863 = 1.645\frac{14300}{\sqrt{n}}

5863\sqrt{n} = 1.645*14300

\sqrt{n} = \frac{1.645*14300}{5863}

(\sqrt{n})^2 = (\frac{1.645*14300}{5863})^2

n = 16

The sample size was of 16.

7 0
3 years ago
Plz someone help me.
satela [25.4K]
Hope this helps you! (and I'm right LOL)


5 0
3 years ago
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