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2 years ago

What is the surface area of this rectangular prism?

Mathematics

1 answer:

Ugo [173]2 years ago

6 0

Answer:

2,700

Step-by-step explanation:

A=2(wl+hl+hw)=2·(20·30+15·30+15·20)=2700

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3m^2-7m-40=0 solve by factoring

Natalija [7]

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3 years ago

What is |-9+4| ? Pls help

Klio2033 [76]

it's 5.

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3 years ago

Read 2 more answers

Frank received a monthly statement for his college savings account. It listed a deposit of $100 as +100.00. It listed a withdraw

artcher [175]

Answer:

Add: $100

Take Out: $25

Total: $835.50

Step-by-step explanation:

A deposit is an amount that is put into the account, by the owner or by someone else.

A withdrawal is an amount that is taken out of the account.

The overall ending balance shows the total amount in the account at the end of the month.

7 0

3 years ago

Custom Office makes a line of executive desks. It is estimated that the total cost for making x units of their Senior Executive

Ivan

Answer:

(a) The average cost function is $\bar{C}(x)=95+\frac{230000}{x}$

(b) The marginal average cost function is $\bar{C}'(x)=-\frac{230000}{x^2}$

(c) The average cost approaches to 95 if the production level is very high.

Step-by-step explanation:

(a) Suppose $C(x)$ is a total cost function. Then the average cost function, denoted by $\bar{C}(x)$ , is

$\frac{C(x)}{x}$

We know that the total cost for making x units of their Senior Executive model is given by the function

$C(x) = 95x + 230000$

The average cost function is

$\bar{C}(x)=\frac{C(x)}{x}=\frac{95x + 230000}{x} \\\bar{C}(x)=95+\frac{230000}{x}$

(b) The derivative $\bar{C}'(x)$ of the average cost function, called the marginal average cost function, measures the rate of change of the average cost function with respect to the number of units produced.

The marginal average cost function is

$\bar{C}'(x)=\frac{d}{dx}\left(95+\frac{230000}{x}\right)\\\\\mathrm{Apply\:the\:Sum/Difference\:Rule}:\quad \left(f\pm g\right)'=f\:'\pm g\\\\\frac{d}{dx}\left(95\right)+\frac{d}{dx}\left(\frac{230000}{x}\right)\\\\\bar{C}'(x)=-\frac{230000}{x^2}$

(c) The average cost approaches to 95 if the production level is very high.

$\lim_{x \to \infty} (\bar{C}(x))=\lim_{x \to \infty} (95+\frac{230000}{x})\\\\\lim _{x\to a}\left[f\left(x\right)\pm g\left(x\right)\right]=\lim _{x\to a}f\left(x\right)\pm \lim _{x\to a}g\left(x\right)\\\\=\lim _{x\to \infty \:}\left(95\right)+\lim _{x\to \infty \:}\left(\frac{230000}{x}\right)\\\\\lim _{x\to a}c=c\\\lim _{x\to \infty \:}\left(95\right)=95\\\\\mathrm{Apply\:Infinity\:Property:}\:\lim _{x\to \infty }\left(\frac{c}{x^a}\right)=0\\\lim_{x \to \infty} (\frac{230000}{x} )=0$

$\lim_{x \to \infty} (\bar{C}(x))=\lim_{x \to \infty} (95+\frac{230000}{x})= 95$

6 0

3 years ago

Suppose f(x)= x? - 6r? +9x and g(x)=10x-6.

stellarik [79]

Answer:

f ( 10 x − 6 ) = 1000 x^ 3 − 1800 x ^2+ 1170 x − 306

Step-by-step explanation:

4 0

2 years ago