Answer:
Step-by-step explanation:
Here a equation of the line is given to us and we need to find out the equation of line which passes through the given point and parallel to the given line , the given equation is ,
Firstly convert it into <em>s</em><em>l</em><em>o</em><em>p</em><em>e</em><em> </em><em>i</em><em>n</em><em>t</em><em>e</em><em>r</em><em>c</em><em>e</em><em>p</em><em>t</em><em> </em><em>f</em><em>o</em><em>r</em><em>m</em><em> </em>of the line which is <u>y</u><u> </u><u>=</u><u> </u><u>m</u><u>x</u><u> </u><u>+</u><u> </u><u>x</u><u> </u>, as ;
On comparing it to <em>y</em><em> </em><em>=</em><em> </em><em>m</em><em>x</em><em> </em><em>+</em><em> </em><em>c</em><em> </em>, we have ,
Now as we know that the <em>s</em><em>l</em><em>o</em><em>p</em><em>e</em><em> </em><em>o</em><em>f</em><em> </em><em>t</em><em>w</em><em>o</em><em> </em><em>p</em><em>a</em><em>r</em><em>a</em><em>l</em><em>l</em><em>e</em><em>l</em><em> </em><em>l</em><em>i</em><em>n</em><em>e</em><em>s</em><em> </em><em>i</em><em>s</em><em> </em><em>s</em><em>a</em><em>m</em><em>e</em><em> </em>. Therefore the slope of the parallel line will be ,
Now we may use <em>p</em><em>o</em><em>i</em><em>n</em><em>t</em><em> </em><em>s</em><em>l</em><em>o</em><em>p</em><em>e</em><em> </em><em>f</em><em>o</em><em>r</em><em>m</em><em> </em>of the line as ,
On substituting the respective values ,
Again the equation can be rewritten as ,
Answer: compass and straightedge or ruler
Perpendicular bisector of a line segment
Geometry construction using a compass and straightedge
compass and straightedge or ruler
Step-by-step explanation:
Answer:
Step-by-step explanation:
What you have is a square and a rectangle
The formula to find the area of a square is
(you only need one side as they are all the same)
The formula for a rectangle is
Then you add them both up
Answer:
look at the photo....................
A) Substitution
substitute y = 5x-2 for y in the first equation and solve for x:
5x-2 = 7x-8 subtract 7x from both sides
-2x-2 = -8 now add 2 to both sides
-2x = -8 + 2 simplify
-2x = -6 divide both sides by -2
x=3
Now substitute x with 3 in either equation
y=5x-2 =5*3-2 =13
(3,13)
B) (3,13) is the point where the two lines intersect
y=mx+b is the equation of a line