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Levart [38]
2 years ago
12

HELPPP PLS show work

Mathematics
1 answer:
hram777 [196]2 years ago
4 0
So in this question, we’re gonna use the sine trigonometric ratio, which equals opposite/hypotenuse.

sin32° = x (the opposite angle)/ 10 (the hypotenuse)

Then rearrange the equation to solve for x:
(10)(sin32°) = x

[Solve for sine using a calculator!]

(10)(0.529919264) = x

[Multiply]

5.299192642 = x

[Round to the nearest tenth]

x ≈ 5.3


I hope this helped!
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Let g be the function given by g(x)=limh→0sin(x h)−sinxh. What is the instantaneous rate of change of g with respect to x at x=π
lorasvet [3.4K]

The <em>instantaneous</em> rate of change of <em>g</em> with respect to <em>x</em> at <em>x = π/3</em> is <em>1/2</em>.

<h3>How to determine the instantaneous rate of change of a given function</h3>

The <em>instantaneous</em> rate of change at a given value of x can be found by concept of derivative, which is described below:

g(x) =  \lim_{h \to 0} \frac{f(x+h)-f(x)}{h}

Where h is the <em>difference</em> rate.

In this question we must find an expression for the <em>instantaneous</em> rate of change of g if f(x) = \sin x and evaluate the resulting expression for x = \frac{\pi}{3}. Then, we have the following procedure below:

g(x) =  \lim_{h \to 0} \frac{\sin (x+h)-\sin x}{h}

g(x) =  \lim_{h \to 0} \frac{\sin x\cdot \cos h +\sin h\cdot \cos x -\sin x}{h}

g(x) =  \lim_{h \to 0} \frac{\sin h}{h}\cdot  \lim_{h \to 0} \cos x

g(x) = \cos x

Now we evaluate g(x) for x = \frac{\pi}{3}:

g\left(\frac{\pi}{3} \right) = \cos \frac{\pi}{3} = \frac{1}{2}

The <em>instantaneous</em> rate of change of <em>g</em> with respect to <em>x</em> at <em>x = π/3</em> is <em>1/2</em>. \blacksquare

To learn more on rates of change, we kindly invite to check this verified question: brainly.com/question/11606037

4 0
2 years ago
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3 years ago
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Answer:A

Step-by-step explanation:

1 bottle is 1.50

4*1.50=5

5+1.25= the total

5divided by 7=0.70

Double check your work I’m not sure if I’m right!

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Answer:

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