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denis23 [38]
2 years ago
13

If ∠G is supplementary to ∠H and the measure of ∠G is 65° what is the measure of ∠H?

Mathematics
1 answer:
Elina [12.6K]2 years ago
7 0

Solution:

<u>Given:</u>

  • ∠G = 65°

Supplementary angles are a pair of angles that sum up to 180°.

<u>It should be noted:</u>

  • If ∠G and ∠H are a pair of supplementary angles, they both sum up to 180°.

Equation formed: ∠G + ∠H = 180

<u>Substitute the values into the equation.</u>

  • ∠G + ∠H = 180
  • => 65 + ∠H = 180

<u>Subtract 65 both sides.</u>

  • => 65 - 65 + ∠H = 180 - 65
  • => ∠H = 180 - 65 = 115°

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Answer:

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Step-by-step explanation:

So we can use the fact that \frac{AN}{FN} =\frac{OR}{FR}

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Manipulating the equation above to solve for AN we have AN = \frac{(FN)(OR)}{FR}

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243 and 2 over 5

Multiply

(−243) and 2 over 5 . −486 over 5.

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−486 over 5

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Decimal Form:

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If the two terms of a gemotric sequence are a1=216, and a2=72, which is the third term? a3?
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GEOMETRIC \: \: PROGRESSIONS \\ \\ \\\\Let \: the \: G.P. \: be \: \: A \: , \: Ar \: , \: A {r}^{2} \: ... \\ \\ Where \:first \: term \: is \: \: A \: \: \\ and \: common \: ratio \: is \: \: R \\ \\ Let \: An \: denotes \: the \: \: nth \: term \: of \: \\ the \: given \: Geometric \: Progression \: \\ \\ It \: is \: given \: - \\ \\ A1 \: = \: 72 \\ \\ A2 \: = \: 216 \\ \\ Common \: ratio \: = \: \frac{A2}{A1} = \frac{216}{72} \\ \\ R = 3 \\ \\ A \: = \: 72 \\ \\ A3 \: = \: A {r}^{2} = 72 \times 3 \times 3 \\ \\ \\ Hence \: , \: A3 \: = \: 648 \: \: \: \: \: \: \: Ans.
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Answer:

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Step-by-step explanation:

1.) standardize by subtracting the mean and dividng by the standard deviation

(625-1000)/125= -3

go to a ztable to get .0013 or (1-.9987)

this is equal to .13%

2.)

875<x<1125

standardize both seperately and subtract them

(875-1000)/125= -1  whose probability is .1587 (or 1-.8413)

(1125-1000)/125= 1  whose probability is .8413

.8413-.1587= 68.26%

3.)

Find the probability that someone paid less than 1250 and take its compliment

(1250-1000)/125= 2 which has a probability of .9772

take its compliment (1-.9772)= .0228= 2.28%

4.)

Same process as question 2

(750-1000)/125= -2 which has a probability of (1-.9772) = .0228

(1000-1000)/125= 0 which has a probability of .5

.5-.0228= .4772= 47.72%

5.) same deal as the previous question

(625-1000)/125= -3 which has a probability of (1-.9987)= .0013

(1000-1000)/125= 0 which has a probability of .5

.5-.0013= .4987= 49.87%

6.)same deal the previous question

(875-1000)/125= -1 which has a probability of (1-.8413)=.1587

(1000-1000)/125= 0 which has a probability of .5

.5-.1587= .3413= 34.13%

4 0
2 years ago
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