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2 years ago

Could you please answer these

Mathematics

2 answers:

Lostsunrise [7]2 years ago

8 0

Answer:

x = 4, y = 2 or (4, 2)

Step-by-step explanation:

Given :-

2x + 3y = 14 -(1)

x + 3y = 10 -(2)

To Find :-

x and y

Solving :-

Subtract (2) from (1).

=> x = 4

Substituting value of x in Equation 2 :-

4 + 3y = 10

3y = 6

=> y = 2

Solution :-

x = 4, y = 2

IrinaVladis [17]2 years ago

7 0

Step-by-step explanation:

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There are 6 red marbles 4 blue marbles to yellow marbles. Sabrina picks 2 marbles without putting the first one back what is the

Yanka [14]

Answer:

P = 3/11

Step-by-step explanation:

There are:

6 red marbles

4 blue marbles

2 yellow marbles.

So there are a total of 12 marbles in the bag, such that each one has the same probability of being randomly picked.

We want to find the probability that the first pick is not yellow (so it can be either blue or red), and the second pick is a blue marble.

Now there are two cases.

The first marble is red and the second blue

the first marble is blue and the second blue

We need to find the probability in each case.

The probability that the first marble is red is equal to the quotient between the number of red marbles (6) and the total number of marbles (12)

p = 6/12

Now, for the second draw, we need a blue marble, the probability in this case is the quotient between the number of blue marbles (4) and the total number of marbles in the bag (now there are 11, because one is already taken)

q = 4/11

The joint probability is equal to the product of the individual probabilities, then:

P₁ = p*q = (6/12)*(4/11) = 2/11

And for the other case, we draw two blue marbles:

For the first draw, the probability is:

p = 4/12

And for the second draw, now there are 3 blue marbles and 11 total marbles, then the probability is:

q = 3/11

The joint probability is:

P₂ = (4/12)*(3/11) = 1/11

The total probability is then:

P = P₁ + P₂ = 2/11 + 1/11 = 3/11

4 0

3 years ago

Neil is a drummer who purchases his drumsticks online. When practicing with the newest pair, he notices they feel heavier than u

Fynjy0 [20]

Answer:

The probability of the stick's weight being 2.33 oz or greater is 0.0041 or 0.41%.

Step-by-step explanation:

Given:

Weight of a given sample (x) = 2.33 oz

Mean weight (μ) = 1.75 oz

Standard deviation (σ) = 0.22 oz

The distribution is normal distribution.

So, first, we will find the z-score of the distribution using the formula:

$z=\frac{x-\mu}{\sigma}$

Plug in the values and solve for 'z'. This gives,

$z=\frac{2.33-1.75}{0.22}=2.64$

So, the z-score of the distribution is 2.64.

Now, we need the probability $P(x\geq 2.33 )=P(z\geq 2.64)$ .

From the normal distribution table for z-score equal to 2.64, the value of the probability is 0.9959. This is the area to the left of the curve or less than z-score value.

But, we need area more than the z-score value. So, the area is:

$P(z\geq 2.64)=1-0.9959=0.0041=0.41\%$