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expeople1 [14]
3 years ago
9

How many three-digit even numbers are possible if the leftmost digit cannot be zero?

Mathematics
1 answer:
Sonbull [250]3 years ago
5 0

Answer:

  450

Step-by-step explanation:

There are 900 3-digit numbers in the range 100–999. Of those, exactly half are even numbers.

There are 450 even three-digit numbers.

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Write a sentence to represent the solution set in the context of the problem.
Nikolay [14]

Answer:

6 sales

Step-by-step explanation:

(I MADE THIS QUESTION I DIDINT KNOW IF YOU NEEDED IT)

Jake wants to but the new computer(it costs $920). Jake has $560 saved in his bank. Jake also gets $60 whenever he makes a sale at his job. How many sale(s) at his job does Jake need to make? <em>Answer </em>-- Jake needs to make 6 sales of $60 to buy the new computer.

MATH -----

$6 x $60 = $360

$360 + $560 = $920

6 0
2 years ago
The width of a rectangle is 2x ^2 +9x -7 and length is x^2 -9
lesantik [10]

Answer:

63 - 81x - 25x² + 9x³ + 2x⁴

Step-by-step explanation:

Multiply the two polynomials to arrive at your answer I guess, since this was not specific enough.

I am joyous to assist you anytime.

7 0
3 years ago
What are the features of the parabola modeled by the equation f(x) = x2 - 114x ?
notsponge [240]

Answer:

Answers are in bold type

Step-by-step explanation:

f(x) = x^{2} -144x

The parabola opens up, so has a minimum at the vertex.

Let (h, k) be the vertex

h = -b/2a = - (-144)/2(1) = 57

k = 57^2 - 144(57) = 3249 - 6498 = -3249

Therefore, the vertex is (57, -3249)

The minimum value is -3249

The domain is the set of real numbers.  

The  range = {y | y ≥ -3249}

The function decreases when -∞ < x < 57  and increases when 57 > x > ∞

The x - intercepts:  x^{2} -144x = 0

                                x(x - 114x) = 0

                                x = 0 or x = 114

x-intercepts are (0, 0) and (0, 114)

When x = 0, then we get the y-intercept.  So, 0^2 - 114(0) = 0

y-intercept is (0, 0)

3 0
4 years ago
How much money would you need to deposit today at 5% annual interest compounded monthly to have $20000 in the account after 9 ye
mario62 [17]
20000=p(1+0.05/12)^12*9
Solve for p
P=20,000÷(1+0.05÷12)^(12×9)
P=12,764.49
7 0
4 years ago
Read 2 more answers
Can someone help will mark brainlist
Marina86 [1]

Answer:

See below

Step-by-step explanation:

the common ratio, r <1    so it CONVERGES    (r = 1/2 in this series)

sum = a1 ( 1-r^n) / (1-r) =  1000(1-.5^10)/(1-1/2) = ~1998

    for n= 30    this results in ~~2000

As it continues, the terms get smaller and smaller and the SUM converges on 2000.

3 0
2 years ago
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