How many three-digit even numbers are possible if the leftmost digit cannot be zero?
1 answer:
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Answer:
Step-by-step explanation:
Simply use the fact that the change in x squared + the change in y squared = the distance squared. (The Pythagorean Theorem)
1^2 + 4^2 = d^2
1 + 16 = d^2
17 = d^2
d = √17
Hope it helps :)
