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2 years ago

If someone could dig a safe tunnel through the earth how long would it take to free fall to the center?

Biology

1 answer:

Reptile [31]2 years ago

6 0

Answer: A scenario often presented to introductory physics classes is that of a "gravity tunnel" — a tube drilled from one side of the Earth to the other through the planet's center. The answer taught for nearly a half-century for how long a fall through such a hole would take was about 42 minutes and 12 seconds.

Explanation: However, solar and lunar gravity, which also perturb orbiting satellites, would eventually pull you into the tunnel wall anyway [source: Darling ]. Strike a chord: Fun fact: A straight line from any point to any other point through the planet would take the same amount of time to fall through like a tunnel through Earth's center.

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Explain how pollution from one location

kati45 [8]

Answer:

Air quality is affected by natural processes. Wind can move pollutants from their source to far-away locations. It can still spread and harm living creatures and destroy their environments.

Explanation:

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2 years ago

Some unicellular organisms are similar to _______ because they have the ability to _______.

stellarik [79]

Some unicellular organisms are similar to animals because they have the ability to move.
Third option

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3 years ago

Read 2 more answers

I need to list the order of traits from sponges to mammals in which they appear from an evolutionary standpoint. I don't know ho

lesya692 [45]

Answer:

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Explanation:

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3 years ago

Which of the following statements explains why the sugar glider and the flying squirrel both have the ability to glide? A) Both

AlexFokin [52]

D is the correct answer since all others are highly unlikely.

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3 years ago

How many possible open reading frames (frames without stop codons) are there that extend through the following sequence? 5'... C

fenix001 [56]

Answer:

There are 4 reading frames without stop codons.

Explanation:

1) To find the possible reading frames you need to separate your sequence in codons (trios) for the 5'-> 3' sense, first, excluding the first nucleotide, then excluding 2 nucleotides and then not excluding nucleotides.

5'... C TTA CAG TTT ATT GAT ACG GAG AAG G... 3' NO STOP CODON

5'... CT TAC AGT TTA TTG ATA CGG AGA AGG... 3' NO STOP CODON

5'... CTT ACA GTT TAT TGA TAC GGA GAA GG... 3'

2)Then you find the complementary sequence (which you already have)

3'... GAA TGT CAA ATA ACT ATG CCT CTT CC... 5'

3'... GA ATG TCA AAT AAC TAT GCC TCT TCC... 5'

3'... G AAT GTC AAA TAA CTA TGC CTC TTC C... 5'

3) Next, you have to obtain the reverse complementary

CCT TCT CCG TAT CAA TAA ACT GTA AG NO STOP CODON

CC TTC TCC GTA TCA ATA AAC TGT AAG NO STOP CODON

C CTT CTC CGT ATC AAT AAA CTG TAA G

4)Now you need to find start (AGT in terms of DNA) and stop codons(TAA, TAG, TGA, also in terms of DNA), in 5->3 and de reverse complementary.

As you can see, you have for open reading frames that lack of stop codon, unfortunately, they also lack of AGT, the start codon.

I added a table where you can find thestart and stop codons as well as the proteins that they translate to in terms of RNA.

I hope you find this information interesting and useful, good luck!

8 0

3 years ago