I believe that the answer to your question is: 2.2409 x 10^4
Answer:
-2.5
Step-by-step explanation:
(4/25)^(-1/2)
= (4/25)^(-1 * 1/2)
=(25/4)^(1/2)
=square root (25/4)
=square root 25 / square root 4
=5/2
-2.5
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To determine the probability, the formula is by number of successful outcomes divided by number of possible outcomes. The number of possible outcomes in this problem is 4.
So to compute the probability distribution:
The number of times that 0 G appeared is 0.25 which is represented by BB which is 1/4.
The number of times that 1 G appeared is .5 which is represented by BG and GB which is 2/4.
The number of times that 2 G appeared is .25 which is represented by GG which is 1/4.
The probability distribution will look like this:
X Px(x)
0 .25
1 .5
2 .25
Don't really need to post the options to know what the expression(s) should look like.
"Sum of" tells you its addition and because it's addition the order of the two terms (the 3 and the N) don't matter.
Your correct expressions are:
3 + n
or
n + 3
Problem 1
Answers:
Domain: 
Range: 
--------------------
Explanation:
The domain is the set of allowed x inputs of a function. The smallest x value we can use is x = -3 (note the very left-most point of the graph). The right-most point involves x = 5, but we can't actually use this x value due to the open hole. So that's why we don't have "or equal to" attached to the 5.
The range is the set of possible y outputs. The lowest we can go is y = -4, but we don't include this as part of the range. The largest y can get is y = 3. So the range is 
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Problem 2
Answers:
Domain: 
Range: 
--------------------
Explanation:
We use the same idea as in problem 1. Both endpoints are open holes, so we don't include them as part of the domain and range. For instance, we can't include x = 4 but we can get closer and closer to it. The same idea applies to the range as well.
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Problem 3
Answers:
Domain: 
Range: 
--------------------
Explanation:
The same idea applies as used earlier. This time we include both endpoints, so we have "or equal to" as part of each inequality sign.