I'm going with B Pennt is seling candles for 4$ each at a fund raiser if I'm right please give me branlest
The point-slope form of a line is:
y-y1=m(x-x1), where m=slope and (x1,y1) is any point on the line
First we need to find the slope, which is (y2-y1)/(x2-x1)
m=(4--1)/(8-2)
m=5/6 and we can use either point, I'll use (8,4)
y-4=(5/6)(x-8)
That is your equation in point-slope form.
Now the standard equation of a line is ax+by=c
y-4=(5/6)(x-8) we can perform the indicated multiplication on the right side
y-4=(5x-40)/6 multiply both sides by 6
6y-24=5x-40 add 24 to both sides
6y=5x-16 subtract 5x from both sides
-5x+6y=-16 and by convention, the standard equation of a line should be expressed with a positive coefficient for x, so multiply both sides by -1
5x-6y=16
Answer:
125i.
Step-by-step explanation:
5^3 is 125 i^2 is -1 so i^8 is positive and you have 1 i left.
Answer: 3 and 7
Step-by-step explanation:
Hope this helps :)
Answer:
Step-by-step explanation:
Challenge # 1
Line has a negative slope with positive slope.
Therefore, equation will be,
y = 1.5x - 6
Parallel line to the given line will have same slope = 1.5 but with different y-intercept.
Equation of the parallel line → y = 1.5x + 6
Challenge # 2
Line has a negative y-intercept = -1 (Approx.)
Slope of the line = negative
Therefore, equation of the line will be,
y = -3.7x -1
Line parallel to the given line will have same slope but different y-intercept.
Equation of the parallel line → y = -3.7x + 1
Challenge # 3
Line with negative slope and no y-intercept.
y = -0.8x
Parallel line to the given line will have same slope and different y-intercept.
Equation of the parallel line → y = -0.8x + 1
Challenge # 4
Line in the graph has positive slope and negative y-intercept.
y = -5 + 4.2x
Line parallel to the given line will have same slope but different y-intercept.
Equation of the parallel line → y = - 7 + 4.2x
