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3 years ago

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Mathematics

1 answer:

SpyIntel [72]3 years ago

4 0

zyy-ebxj-frk come

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Given: 11x-6y=-1; x=8

wolverine [178]

To solve this, simply substiture 8 in for x, and solve for y.

11(8) -6y = -1

Multiply 11 by 8

88 - 6y = -1

Subtract 88 from each side of the equation.

-6y = -89

Lastly divide each side of the equation by -6

y = 89/6 is your answer.

Hope this helps!

5 0

3 years ago

Pls help i dont get i t

zmey [24]

Answer:

$4.80

Step-by-step explanation:

6 oranges for 1.80

sp 6 divided by 1.80 comes out to 0.3 per orange

0.3 times 16 comes out to 4.80

therefor $4.80

4 0

3 years ago

Read 2 more answers

Please answer this it’s not answered on brainly yet

Tema [17]

Answer:

125.92 sq cm

Step-by-step explanation:

You need to find the area of all the sides, so:

2(2.2 * 9.1) + 2(2.2 * 3.8) + 2( 9.1 * 3.8)

= 125.92 sq cm

4 0

3 years ago

Read 2 more answers

I got 67, is it right? Solve for angle A of the right triangle

Lina20 [59]

I think it would be 37 hope this helps:)

8 0

3 years ago

) An instructor gives his class a set of 18 problems with the information that the next quiz will consist of a random selection

RSB [31]

Answer:

The probability the he or she will answer correctly is 1.5%

Step-by-step explanation:

In all, there are 18 problems. In this question, the order of which the problems are sorted for the quiz makes no difference. For example, if the question A of the quiz is P1 and question B P2, and question A P2 and question B P1, it is the same thing.

There are 18 problems and 9 are going to be selected. So, there is going to be a combination of 9 elements from a set of 18 elements.

A combination of n elements from a set of m objects has the following formula:

$C_{(m,n)} = \frac{m!}{n!(m-n)!}$

In this question, m = 18, n = 9. So the total number of possibilities is:

$T_{p} = C_{(18,9)} = \frac{18!}{9!(18-9)!} = 48620$

Now we have to calculate the number of desired outcomes. This number is a combination of 9 elements from a set of 13 elements(13 is the number of problems that the student has figured out how to do).

Now, m = 13, n = 9. The number of desired possibilities is:

$D_{p} = C_{(13,9)} = \frac{13!}{9!(13-9)!} = 715$

The probability is the number of desired possibilities divided by the number of total possibilities. So

$P = \frac{715}{48620} = 0.015 = 1.5%$

The probability the he or she will answer correctly is 1.5%

3 0

3 years ago