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horrorfan [7]
2 years ago
7

CAN ANYBODY PLEASE HELP ME FOR BRAINLIEST, I'VE BEEN ASKING FOR DAYS AND POSTING DAILY THE SAME QUESTION :(

Mathematics
1 answer:
kvv77 [185]2 years ago
3 0

Answer:  y = 650(0.907)^t

This is the same as writing y = 650(0.907)^t

=====================================================

Explanation:

Exponential equations can be of the form y = a*b^t

  • a = initial amount
  • b = growth or decay factor

In this case, we have

  • a = 650 mg to start with
  • b = 1 - 0.093 = 0.907 as the decay factor

If we had exponential growth, then we'd compute 1 + 0.093 instead.

Based on those values, we go from y = a*b^t to y = 650(0.907)^t which is the same as writing y = 650(0.907)^t

Other exponential forms are possible, but I think this form is the most intuitive. The 0.907 means that 90.7% of the sample remains after each year.

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Mustafa contributes 11% of his $67,200 annual salary to his 401k plan. What is his pretax income
skad [1K]

Answer:

Mustafa's pretax income is $59,808.

Step-by-step explanation:

Given in the question Mustafa's annual salary = $67,200

and Mustafa contribute 11% of his salary to his 401 k plan.

Since we know that 401 k plan is a retirement plan in which an employee gets the exemption from his salary on a pretax basis.

Therefore exemption will be = 11% of $67,200

                                               = 67,200×0.11

                                               = $7,392

Now pretax income or taxable income = 67,200-7,392 = $59,808

Therefore pretax income of Mustafa is $59,808.

4 0
2 years ago
A basketball player is shooting a basketball toward the net. The height, in feet, of the ball t seconds after the shot is modele
aev [14]

THIS IS THE COMPLETE QUESTION

basketball player is shooting a basketball toward the net. The height, in feet, of the ball t seconds after the shot is modeled by the equation h = 6 + 30t – 16t2. Two-tenths of a second after the shot is launched, an opposing player leaps up to block the shot. The height of the shot blocker’s outstretched hands t seconds after he leaps is modeled by the equation h = 9 + 25t – 16t2. If the ball reaches the net 1.7 seconds after the shooter launches it, does the leaping player block the shot?

Yes, exactly 0.6 seconds after the shot is launched.

Yes, between 0.64 seconds and 0.65 seconds after the shot is launched

Yes, between 0.84 seconds and 0.85 seconds after the shot is launched.

No, the shot is not blocked.

Answer:

Yes, between 0.84 seconds and 0.85 seconds after the shot is launched.

Given that the

equation for shot block height h = 9 + 25t – 16t2.

equation for ball height h = 6 + 30t – 16t2.

From the question ,it can be deducted that the shot is made before two tenths of a second or 0.2seconds

CHECK THE ATTACHMENT TO COMPLETE THE DETAILED SOLUTION

5 0
3 years ago
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marysya [2.9K]
X+3 or x-8
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8 0
3 years ago
Idk how to do this 4x+y=1
ivolga24 [154]
4x+y=1
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6 0
3 years ago
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Julli [10]
5.815+6.021= 11.836


good luck!
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3 years ago
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