Please help me... :)
1 answer:
Part 1
There are many ways to go about this, but one possibility is the following:
You are building a tree house. Your ladder is 10 feet long and the portion in the tree you're trying to get to is 8 feet off the ground. How far should the base of the ladder be from the tree so you can reach that portion?
==========================================================
Part 2
The drawing is shown below. The diagram is shown in 2D to keep things as simple as possible. Adding a third dimension greatly complicates everything.
We have a right triangle, so it has a 90 degree angle as shown by the square marker. The vertical leg is 8 feet. The horizontal leg is unknown. The hypotenuse (longest side) is 10 feet long to indicate the ladder.
==========================================================
Part 3
Use the pythagorean theorem to get...
a^2 + b^2 = c^2
x^2 + 8^2 = 10^2
x^2 + 64 = 100
x^2 = 100-64
x^2 = 36
x = sqrt(36)
x = 6
The base of the ladder should be 6 feet away from the tree, so that you can reach 8 feet off the ground.
You might be interested in
Answer:
ED: 6.5 cm BE = 14.4 cm
Step-by-step explanation:
Add 20 and 5 to get side AC.
25/20 gives us the scale factor to go from 25 triangle ABE to triangle ACD.
Multiply 26 by the SF to get AD.
Subtract length of AD by AE to get ED. You should get 6.5 cm (don't forget units!!!!)
To go from triangle ACD to triangle ABE, we can do 20/25 to get the scale factor.
Using that number, multiply it with 18 to get BE.
The answer should be 14.4 cm.
This is possible because the two triangles ACD and ABE are similar via the angle angle angle similarity theorem depicted in my screenshot.
Answer:
hey here is the correct answer
