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Firdavs [7]
3 years ago
8

Why are certain bacterial infections difficult to treat with antibiotics?

Biology
1 answer:
deff fn [24]3 years ago
5 0

Answer:

When the Bacteria becomes resistant, the germs spread and grow. In some cases they can they can spread the resistance onto other bacteria's

Explanation:

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BMI is the calculation based on a person's weight and _______.
Liono4ka [1.6K]
BMI is the calculation based on a person's weight and height.
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3 years ago
Read 2 more answers
What is the name for a place where a particular organism lives?
umka21 [38]

Trees, bushes, moss and grass live in a forest habitat.

4 0
3 years ago
The majority of the U.S. population will take a pain reliever that doubles as a fever reducer at the first hint of illness.
krek1111 [17]

Answer:

This is not the best practice because the fever is a mechanism of the body against infection since it will raise the body temperature bacteria, which live well below 37 ° C, die, however it is noteworthy that by itself the fiber can not cure an infection but defenses are needed and must be treated with antibiotics.

In addition, in a small percentage of cases the fever becomes urgent. This is true. It is only true if it exceeds 42 ° C in a sustained manner.

7 0
4 years ago
A plant population produces many seeds. that if a population of plants is currently 30 individuals, and rmax= 12 plants/month, t
LiRa [457]

Answer:

\frac{dN}{dt} = 14130

Explanation:

Logistic growth is a measure of continuous growth of a population of individuals in such an environment where the resources are limited. Such type of growth pattern has a characteristic growth curve which is S-shaped or sigmoidal.

The equation for logistic growth is as follows -

Change in population size = \frac {dN}{dt} = rN(K- \frac {N}{K})

Where,

N = size of population

r = intrinsic rate of increase

K = carrying capacity

The values of r, N and K are given in the question as 12, 30 and 40 respectively.

So,

\frac{dN}{dt} = 12 \times 30(40 - \frac{30}{40}) = 14130

5 0
3 years ago
A brown-eyed man with a blue-eyed mother marries a brown-eyed woman with a blue-eyed father. What is the probability that their
almond37 [142]

This is based on my assumption that brown is dominant over blue.

Since both parent have parents who are homo_zygous recessive, this tells us that both parents will be hetero_zygous.

When you cross two hetero_zygous parents, it can produce these genotypic and phenotypic ratios:

<u>Genotypic</u>

BB : Bb : bb

1 : 2 : 1

<u>Phenotypic</u>

brown : blue

3 : 1

Therefore there is a 75% chance that they will produce a brown-eyed offspring.

6 0
2 years ago
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