Question

What are the first 5 terms of the sequence if; an=2(an-1+an-2), a1=-2, a2=-3?

Answer 1

The answer would be b 
hope that helps

Answer 2

$\boxed { \boxed {a_n=2(a_{n-1} + a_{n-2})}}$

$a_{1} = - 2$

$a_{2} = - 3$

$a_{3}=2(a_{3-1} + a_{3-2}) = 2(a_{2} + a_{1}) = 2(-3 + (-2)) = -10$

$a_{4}=2(a_{4-1} + a_{4-2}) = 2(a_{3} + a_{2}) = 2(-10 + (-3)) = -26$

$a_{5}=2(a_{5-1} + a_{5-2}) = 2(a_{4} + a_{3}) = 2(-26 + (-10)) = -72$

Answer: –2, –3, –10, –26, –72  (Answer C)