All categories

2 years ago

67 - a = 58 What is the value of a

Mathematics

2 answers:

mrs_skeptik [129]2 years ago

7 0

Answer:

a = 9

Step-by-step explanation:

67 - a = 58

67 - 58 = 9

So a = 9

denis-greek [22]2 years ago

4 0

Answer:

67-58=9 it is an answer i think

You might be interested in

Robert wants to install windows in a bus barn to improve the airflow in the summer months. If Robert makes his own screens, he c

DedPeter [7]

=1/2

you add both on each side then subtract 2 from you anser

8 0

3 years ago

ANSWER NOWWW PLEASEEEEWhat operation is represented in the expression 4 (2+4)?

user100 [1]

Product difference would be it

8 0

3 years ago

What is : 65=4u+13 ????

Rus_ich [418]

Answer: 13

Step-by-step explanation:

65-13=54

54/4=13

Order of operations

6 0

3 years ago

Read 2 more answers

Use the quadratic formula to solve the equation x^2-7x-6=0

olganol [36]

Answer:

$\frac{7\pm\sqrt{73}} {2}$

Explanation:

We have been given with the quadratic equation $x^2-7x-6=0$

We have general formula to find the roots of a quadratic equation first we find the discriminant with formula

$D=b^{2}-4ac$

and after that to find the variable suppose x we have the formula

$x=\frac{-b\pm\sqrt{D}} {2a}$

And general quadratic equation is

$ax^2+bx+c=0$

On comparing the given quadratic equation with genral quadratic equation we will have values

a=1, b=-7 and c=-6

After substituting these values in the formula we will get

$D=(-7)^2-4(1)(-6)={73}$

After substituting in the formula to find x we will get

$\frac{-(-7)\pm\sqrt{73}} {2}= \frac{7\pm\sqrt{73}} {2}$

4 0

3 years ago

Read 2 more answers

CALCULUS: For the function whose values are given in the table below, the integral from 0 to 6 of f(x)dx is approximated by a Re

ladessa [460]

The table gives values of f(x) at various x in the interval [0, 6], and you have to use them to approximate the definite integral,

∫₀⁶ f(x) dx

with a left-endpoint sum using 3 intervals of width 2. This means you have to

• split up [0, 6] into 3 subintervals of equal length, namely [0, 2], [2, 4], and [4, 6]

• take the left endpoints of these intervals and the values of f(x) these endpoints, so x ∈ {0, 2, 4} and f(x) ∈ {0, 0.48, 0.84}

• approximate the area under f(x) on [0, 6] with the sum of the areas of rectangles with dimensions 2 × f(x) (that is, width = 2 and height = f(x) for each rectangle)

So the Riemann sum is

∫₀⁶ f(x) dx ≈ 2 ∑ f(x)

for x ∈ {0, 2, 4}, which is about

∫₀⁶ f(x) dx ≈ 2 (0 + 0.48 + 0.84) = 2.64

making the answer A.

7 0

2 years ago