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ella [17]
2 years ago
11

Find the 95th term of the arithmetic sequence 4, -5, -14

Mathematics
1 answer:
poizon [28]2 years ago
3 0

Answer: -842

Step-by-step explanation:

To find n95, we have to use the equation aₙ = d * n + a₁ - d

a₁ is the first term, which here is 4. d is the common difference, which we can find out but seeing what we can add pr subtract from 4 to -5 which also equals -5 to -14, in this equation, the common difference would be -9 as it goes down by 9 every term. Once we plug these into the equation, we get

a₉₅ = -9 * n + 4 - (-9)

We can solve this for - aₙ = -9n + 13

Now that we have our equation to find a term, we can plug in n for 95 for

-9(95) + 13

Which equals -842

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Which number is composite?<br> a. 79<br> b. 87<br> c. 89<br> d. 97
n200080 [17]
I am pretty sure b. is right. This is because 87 is not prime
8 0
3 years ago
How far does a horse travel if it gallops at an average speed of 25 km/h for 30 min?
marishachu [46]

Answer:

12.5 km.

Step-by-step explanation:

Distance = average speed x time = 25 km/h x 0.5 h = 12.5 km.

if wrong, sorry

(but most likely right)

4 0
2 years ago
The sum of a number and its reciprocal is 41/20. Find the number. smaller value larger value
Natali [406]

Step-by-step explanation:

Let the number is x. Its reciprocal will be 1/x. According to given condition, we get :

x+\dfrac{1}{x}=\dfrac{41}{20}\\\\\dfrac{x^2+1}{x}=\dfrac{41}{20}\\\\20x^2+20=41x\\\\20x^2-41x+20=0

It is a quadratic equation. The values of x are :

20x^2-25x - 16x+ 20 =0\\\\5x(4x - 5) -4( 4x - 5) = 0\\\\(5x-4)(4x-5)=0\\\\5x-4=0\ \text{and}\ (4x-5)=0\\\\x=\dfrac{4}{5}\ \text{and}\ x=\dfrac{5}{4}

The smaller number is 4/5 and the larger number is 5/4.

6 0
3 years ago
Ill give you Brainlyest! I need help ASAP work shown, please!!<br> problems 8-15
8_murik_8 [283]

Using the segment addition theorem, the solutions are:

5. x = 17

6. x = 7

7. x = 14

BC = 27

CD = 61

BD = 88

8. AB = 26

9. LJ = 46

10. x = 3

11. FG = 15

12. QS = 34

13. BC = 26

14. EG = 19

15. QS = 68

<h3>How to Apply the Segment Addition Theorem?</h3>

The segment addition theorem would be used to solve the problems as shown below:

5. UW = UV + VW [segment addition theorem]

Substitute

6x - 35 = 19 + 4x - 20

6x - 4x = 35 + 19 - 20

2x = 34

x = 17

6. HJ = HI + IJ [segment addition theorem]

Substitute

7x - 27 = 3x - 5 + x - 1

7x - 3x - x = 27 - 5 - 1

3x = 21

x = 7

7. BD = BC + CD [segment addition theorem]

Substitute

7x - 10 = 4x - 29 + 5x - 9

7x - 4x - 5x = 10 - 29 - 9

-2x = -28

x = 14

BC = 4x - 29 = 4(14) - 29 = 27

CD = 5x - 9 = 5(14) - 9 = 61

BD = 7x - 10 = 7(14) - 10 = 88

8. BC = BD

Substitute

2x + 1 = 5x - 26

2x - 5x = -1 - 26

-3x = -27

x = 9

AB = 43 - BC

AB = 43 - 2x + 1 = 43 - 2(9) + 1 = 26

9. 7x - 10 = 9x - 11 - (x + 3)

7x - 10 = 9x - 11 - x - 3

7x - 9x + x = 10 - 11 - 3

-x = -4

x = 4

LJ = 28 + 7x - 10 = 28 + 7(4) - 10

LJ = 46

10. 8x + 11 = 12x - 1

8x - 12x = -11 - 1

-4x = -12

x = 3

11. 11x - 7 = 3x + 9

11x - 3x = 7 + 9

8x = 16

x = 2

FG = 11x - 7 = 11(2) - 7

FG = 15

12. 5x - 3 = 21 - x

5x + x = 21 + 3

6x = 24

x = 4

QS = 2(5x - 3) = 10x - 6 = 10(4) - 6

QS = 34

13. 8x - 20 = 2(3x - 1)

8x - 20 = 6x - 2

8x - 6x = 20 - 2

2x = 18

x = 9

BC = AB = 3x - 1 = 3(9) - 1

BC = 26

14. 5x - 1 = 7x - 13

5x - 7x = 1 - 13

-2x = -12

x = 6

EG = 6x - 4 - 13 = 6(6) - 4 - 13

EG = 19

15. RT - ST = RS

Substitute

8x - 43 - (4x - 1) = 2x - 4

8x - 43 - 4x + 1 = 2x - 4

4x - 42 = 2x - 4

4x - 2x = 42 - 4

2x = 38

x = 19

QS = 2(RS)

QS = 2(2x - 4) = 4x - 8 = 4(19) - 8

QS = 68

Learn more about the segment addition theorem on:

brainly.com/question/28263183

#SPJ1

8 0
1 year ago
A movie theater problem I need help with
Sever21 [200]

What's 18 × 15 ?







Hint : 270

4 0
3 years ago
Read 2 more answers
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