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3 years ago

Solve: 2 in 3 = in (x-4)

Mathematics

1 answer:

Bogdan [553]3 years ago

3 0

Answer:

-6.59

Step-by-step explanation:

just try it and see

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5[3(x+4)-2(1-x)]-x-15=14x+55 what is x

Nostrana [21]

Answer:

x=2

Step-by-step explanation:

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3 years ago

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artcher [175]

This is an exponential table

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3 years ago

Took Gage 1 of a gallon of paint to create a mural of his favorite team the Grizzlies. He was asked to replicate his mural for 8

Charra [1.4K]

Answer: He will need 8 gallons of paint for the other murals.

Step-by-step explanation:

Given: 1 gallon of paint was required to create 1 mural.

Since replicates have the same dimensions, i.e same total surface area.

So, if 8 replication need to be made, the quantity of the paint required for this will be

8 x (Quantity required for 1 mural)

= 8 x 1

= 8 gallons

Hence, he will need 8 gallons of paint for the other murals.

4 0

3 years ago

In Problems 23–30, use the given zero to find the remaining zeros of each function

Talja [164]

Answer:

x = 2i, x = -2i and x = 4 are the roots of given polynomial.

Step-by-step explanation:

We are given the following expression in the question:

$f(x) = x^3 - 4x^2+ 4x - 16$

One of the zeroes of the above polynomial is 2i, that is :

$f(x) = x^3 - 4x^2+ 4x - 16\\f(2i) = (2i)^3 - 4(2i)^2+ 4(2i) - 16\\= -8i+ 16+8i-16 = 0$

Thus, we can write

$(x-2i)\text{ is a factor of polynomial }x^3 - 4x^2 + 4x - 16$

Now, we check if -2i is a root of the given polynomial:

$f(x) = x^3 - 4x^2+ 4x - 16\\f(-2i) = (-2i)^3 - 4(-2i)^2+ 4(-2i) - 16\\= 8i+ 16-8i-16 = 0$

Thus, we can write

$(x+2i)\text{ is a factor of polynomial }x^3 - 4x^2 + 4x - 16$

Therefore,

$(x-2i)(x+2i)\text{ is a factor of polynomial }x^3 - 4x^2 + 4x - 16\\(x^2 + 4)\text{ is a factor of polynomial }x^3 - 4x^2 + 4x - 16$

Dividing the given polynomial:

$\displaystyle\frac{x^3 - 4x^2 + 4x - 16}{x^2+4} = x -4$

Thus,

$(x-4)\text{ is a factor of polynomial }x^3 - 4x^2 + 4x - 16$

X = 4 is a root of the given polynomial.

$f(x) = x^3 - 4x^2+ 4x - 16\\f(4) = (4)^3 - 4(4)^2+ 4(4) - 16\\= 64-64+16-16 = 0$

Thus, 2i, -2i and 4 are the roots of given polynomial.

4 0

3 years ago

Evaluate 5^28·5^-32·5^-4<br> A. 17,920<br> B. 0.017920<br> C. 0.000256<br> D. 0.00000256

romanna [79]

Answer:

D 0.00000256

Step-by-step explanation:

$5^{28} *5^{-32}*5^{-4}=5^{28-32-4}=5^{-8}=\frac{1}{5^{8}} =0.00000256$

4 0

3 years ago

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