<h3>
Answer: D) 70</h3>
===========================================================
Explanation:
Label a new point E at the intersection of the diagonals. The goal is to find angle CEB. Notice how angle AED and angle CEB are vertical angles, so angle AED is also x.
Recall that any rectangle has each diagonal that is the same length, and each diagonal cuts each other in half (aka bisect). This must mean segments DE and AE are the same length, and furthermore, triangle AED is isosceles.
Triangle AED being isosceles then tells us that the base angles ADE and DAE are the same measure (both being 55 in this case).
---------------------
To briefly summarize so far, we have these interior angles of triangle ADE
For any triangle, the three angles always add to 180, so,
A+D+E = 180
55+55+x = 180
110+x = 180
x = 180-110
x = 70
Well the are six sides and numbers on the dices and two sides on the coin so there would be 8 outcomes
Step-by-step explanation:
always begin any problem by writing what you know
circumference is
u = 2 pi r
1)
u=3.14
r=?
3.14 = 2 pi r
Solve for r
the rest of the problems you just plug the numbers into the formula
Answer:
sin C = 7/25
cos C = 24/25
tan C = 7/24
Step-by-step explanation:
opposite of C = 7
adjacent of C = 24
hypotenuse of C = 25
sin = opposite / hypotenuse
so sin C = 7/25
cos C = adjacent / hypotenuse
so cos C = 24/25
tan = opposite / adjacent
so tan C = 7/24
Answer:
And if we replace we got:
So we expect about 0.8 defective computes in a batch of 4 selected.
Step-by-step explanation:
Previous concepts
The expected value of a random variable X is the n-th moment about zero of a probability density function f(x) if X is continuous, or the weighted average for a discrete probability distribution, if X is discrete.
Solution to the problem
For this case we have the following distribution given:
X 0 1 2 3 4
P(X) 0.4096 0.4096 0.1536 0.0256 0.0016
And we satisfy that 
and 
so we have a probability distribution. And we can find the expected value with the following formula:
And if we replace we got:
So we expect about 0.8 defective computes in a batch of 4 selected.
