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Kay [80]
3 years ago
6

Dave rolls a die and flips a coin. How many outcomes are in the sample space?

Mathematics
2 answers:
kogti [31]3 years ago
5 0
Well the are six sides and numbers on the dices and two sides on the coin so there would be 8 outcomes

m_a_m_a [10]3 years ago
5 0
There are 12 outcomes when you flip a coin and roll a die, because there are 6 outcomes on the die, and 2 outcomes on the coin, so if you multiply 6 times 2 you get your answer.
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The sum of 7 and three times a number is at least 13
Yuki888 [10]

Answer:

7 + 3x ≥ 13

Step-by-step explanation:

The best way to write this is to truly understand what each of the terms mean. The sum means that multiple terms are added together, which means that 7 and 3 times a number will be added together.

Next, the term three times a number just means 3x. So as of now, we have 7 and 3x being added together.

Finally, the term at least 13 means that the 7 + 3x is greater than or equal to 13. Once everything is put together, you get a final inequality of 7 + 3x ≥ 13.

7 0
2 years ago
Find the absolute maximum and absolute minimum values of f on the given interval. f(t) = 9t + 9 cot(t/2), [π/4, 7π/4]
agasfer [191]

Answer:

the absolute maximum value is 89.96 and

the absolute minimum value is 23.173

Step-by-step explanation:

Here we have cotangent given by the following relation;

cot \theta =\frac{1 }{tan \theta} so that the expression becomes

f(t) = 9t +9/tan(t/2)

Therefore, to look for the point of local extremum, we differentiate, the expression as follows;

f'(t) = \frac{\mathrm{d} \left (9t +9/tan(t/2)  \right )}{\mathrm{d} t} = \frac{9\cdot sin^{2}(t)-\left (9\cdot cos^{2}(t)-18\cdot cos(t)+9  \right )}{2\cdot cos^{2}(t)-4\cdot cos(t)+2}

Equating to 0 and solving gives

\frac{9\cdot sin^{2}(t)-\left (9\cdot cos^{2}(t)-18\cdot cos(t)+9  \right )}{2\cdot cos^{2}(t)-4\cdot cos(t)+2} = 0

t=\frac{4\pi n_1 +\pi }{2} ; t = \frac{4\pi n_2 -\pi }{2}

Where n_i is an integer hence when n₁ = 0 and n₂ = 1 we have t = π/4 and t = 3π/2 respectively

Or we have by chain rule

f'(t) = 9 -(9/2)csc²(t/2)

Equating to zero gives

9 -(9/2)csc²(t/2) = 0

csc²(t/2)  = 2

csc(t/2) = ±√2

The solutions are, in quadrant 1, t/2 = π/4 such that t = π/2 or

in quadrant 2 we have t/2 = π - π/4 so that t = 3π/2

We then evaluate between the given closed interval to find the absolute maximum and absolute minimum as follows;

f(x) for x = π/4, π/2, 3π/2, 7π/2

f(π/4) = 9·π/4 +9/tan(π/8) = 28.7965

f(π/2) = 9·π/2 +9/tan(π/4) = 23.137

f(3π/2) = 9·3π/2 +9/tan(3·π/4) = 33.412

f(7π/2) = 9·7π/2 +9/tan(7π/4) = 89.96

Therefore the absolute maximum value = 89.96 and

the absolute minimum value = 23.173.

7 0
3 years ago
X/5=1/(x+4) solve for x
solmaris [256]

ANSWER:

X is -5 and 1.

1) cross multiply

2) subtract five from both sides

3) factor

4) check for extraneous

5) ask me if you are still confused.

6 0
3 years ago
Jim pays $75 per month for a cell phone plan plus $0.30 per minute beyond the first 1000 minutes. Write an equation for the cost
iragen [17]
The answer is 75+ 0.30(x) = y
8 0
3 years ago
Read 2 more answers
Identify whether the series summation of 16 open parentheses 5 close parentheses to the I minus 1 power from 1 to infinity is a
Svet_ta [14]
We are given with the function summation of 16*(5) ^(I-1) from 1 to infinity. As we assume in the calculator that infinity is equal to a very large number, the result that can be obtained is undefined. This means the number is very large. This is because the ratio (15) is large too. The series is divergent since the number in the infinite geometric series is ever increasing. Answer is B.
8 0
3 years ago
Read 2 more answers
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