<h2>
Answer:</h2>
a. <-13/2,-13/2>
<h2>
Step-by-step explanation:</h2>
The projection of a vector u onto another vector v is given by;
=
----------------(i)
Where;
u.v is the dot product of vectors u and v
|v| is the magnitude of vector v
Given:
u = <-6, -7>
v = <1, 1>
These can be re-written in unit vector notation as;
u = -6i -7j
v = i + j
<em>Now;</em>
<em>Let's find the following</em>
(i) u . v
u . v = (-6i - 7j) . (i + j)
u . v = (-6i) (1i) + (-7j)(1j) [Remember that, i.i = j.j = 1]
u . v = -6 -7 = -13
(ii) |v|
|v| = 
|v| = 
<em>Substitute these values into equation (i) as follows;</em>
= ![[\frac{-13}{(\sqrt{2}) ^2}][i + j]](https://tex.z-dn.net/?f=%5B%5Cfrac%7B-13%7D%7B%28%5Csqrt%7B2%7D%29%20%5E2%7D%5D%5Bi%20%2B%20j%5D)
= ![\frac{-13}{2} [i + j]](https://tex.z-dn.net/?f=%5Cfrac%7B-13%7D%7B2%7D%20%5Bi%20%2B%20j%5D)
This can be re-written as;
= 
= 
X is equal to -2/3
if you ever need anymore help with things like this you can go to mathway . com
Answer:

Step-by-step explanation:
Given,
Length ( L ) = 6x - 5
Perimeter of a square ( P ) = ?
<u>Finding </u><u>the </u><u>perimeter </u><u>of </u><u>a </u><u>square </u><u>having </u><u>length </u><u>of </u><u>6</u><u>x</u><u>-</u><u> </u><u>5</u>
( where l is the side of the square )
plug the value of length
⇒
Distribute 4 through the parentheses
⇒
⇒
Hope I helped!
Best regards!!
Answer:
system is:
y = 1/2x
y = 1/2x - 2
No Solution to this system
Step-by-step explanation: