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juin [17]
2 years ago
15

This is geometry II B and i need help on all of them pls?

Mathematics
1 answer:
baherus [9]2 years ago
6 0

Answer:

9) 5.8

10) 27.9

11) 37.1

12) 16.8

Step-by-step explanation:

For this you need to know SOH (sine = opposite/adj) CAH (cos = adj/hypo) and TOA (tan = opp/adj).

For 9, you have one side 15 and one angle 21 degrees.  We can see that relative to the 21 degrees the side lengths, x and 15, are the Opposite and the Adjacent. So we label them "x=O" and "15=A". This means we have Tangent(21) = Opposite "x" /Adjacent "15"

We then evaluate tan21=x/15.

1) To get rid of the fraction multiply 15 on both sides to get 15*tan21=x.

2) Use a calculator to get the answer 5.8 (5.7579..)

For 10, it is the same process but with cosine. You have one side 19 and one angle 47 degrees. We can see that relative to the 21 degrees the side lengths, x and 19, are the Hypotenuse and the Adjacent. So we label them "x=H" and "19=A". This means we have Cosine(47) = Adjacent "19" / Hypotenuse "x"

We then evaluate cos47=19/x.

1) To get rid of the fraction multiply x on both sides to get x*cos47=19.

2) Divide by cos47 on both sides to isolate x. This will be x=47/cos21

3) Use a calculator to get the answer 27.9 (27.8593...)

For 11, refer to how I did question 9 on how it's tan68 = 15/x.

Then refer to question 10 on what to do if x is the denominator (isolate the x).

You should end up with x=15/tan68 which is 37.1 (37.1263...)

Finally for 12, it's the same but for sine (sin=opp/hyp).

You should get that the opp=15 and hypo=x.

That means sin63=15/x which is then x=15/sin63

Answer is 16.8 (16.834...)

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Yesterday, 64% of the 6th grade students chose to drink chocolate milk with their lunch. What fraction of 6th grade students Did
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Answer:

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Step-by-step explanation:

First subtract 100 and 64. To find how many didn't choose to drink chocolate milk.

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3 years ago
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cestrela7 [59]

Answer:

The maximum height of the twig is 96.6 feet off the ground

Step-by-step explanation:

To determine the maximum height of the twig,

First, we will determine the height distance covered by the twig after Mary flicks the twig up.

From the question,

Mary flicks a twig up and off of the ledge with the initial vertical velocity of 10 feet per second, that is

the initial velocity of the twig is 10 feet/second

At maximum height, the final velocity is 0

From on the equations of motions for bodies moving upwards,

v² = u² - 2gh

Where v is the final velocity

u is the initial velocity

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and h is the height

From the question

u = 10 feet/second

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Putting the values into the equation

v² = u² - 2gh

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64.34h = 100

h = 100/64.34

h = 1.6 feet

This is the height distance covered by the twig after Mary flicks it up.

Now, the maximum height of the twig will be the sum of the height of the rooftop from the ground and the height distance covered by the twig.

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Maximum height = 95 feet + 1.6 feet

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Well,

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Since there are no more digits after that, 26.50 must already be rounded to the nearest hundredth.

26.50 is the final answer.
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