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rewona [7]
2 years ago
15

What is the equation of the line that passes through the point (3,-1) and is perpendicular to the equation y= -3x+2?

Mathematics
2 answers:
Sauron [17]2 years ago
6 0

Answer:

i think it is b or d im not for sure though

Step-by-step explanation:

Alex787 [66]2 years ago
6 0
Letter b because when an equation is perpendicular, the slope(in this case, -3) is reversed and the opposite...the slope for this equation would be 1/3 because 1/3 is the 3 reversed and it would be positive because the original equation has a negative
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A minibus drives at a constant speed of 92 km/h. How long will it take to travel a distance of 276 km?
UkoKoshka [18]

Step-by-step explanation:

Distance travelled in 1 hour = 92 km

Time taken to travel 276 km

= 276 / 92

= 3 hours

Hope it will help :)

5 0
3 years ago
Two sides of a triangle have the following measures. Find the range of possible measures for the third side.
Bond [772]

Answer:

x=14.3

Step-by-step explanation:

its the Pythagorean theorem

3 0
3 years ago
Will markk the brainliest
ivolga24 [154]

Answer:

  1. the range of f^-1(x) is {10, 20, 30}.

  2. the graph of f^-1(x) will include the point (0, 3)

  3. n = 8

Step-by-step explanation:

1. The domain of a function is the range of its inverse, and vice versa. The range of f^-1(x) is {10, 20, 30}.

__

2. See above. The domain and range are swapped between a function and its inverse. That means function point (3, 0) will correspond to inverse function point (0, 3).

__

3. The n-th term of an arithmetic sequence is given by ...

  an = a1 +d(n -1)

You are given a1 = 2, a12 = 211, so ...

  211 = 2 + d(12 -1)

  209/11 = d = 19 . . . . . solve the above equation for the common difference

Now, we can use the same equation to find n for an = 135.

  135 = 2 + 19(n -1)

  133/19 = n -1 . . . . . . . subtract 2, divide by 19

  7 +1 = n = 8 . . . . . . . . add 1

135 is the 8th term of the sequence.

3 0
3 years ago
Seven more than twice his age is 51 in algaebric expression
kozerog [31]
7 + 2x = 51

hope this helps
8 0
3 years ago
Read 2 more answers
if alpha and beta are zeroes of the quadratic polynomial f(x) = x2-x-2 then find a polynomial whose zeroes are 2alpha + 1 and 2b
frosja888 [35]

Answer:

Step-by-step explanation:

Hello, as alpha and beta are zeroes of

x^2-x-2

it means that their sum is alpha+beta=1 and their product alpha*beta=-2.

The polynomial whose zeroes are 2 alpha + 1 and 2 beta + 1, means that the sum of its zeroes is 2(alpha+beta)+2=2+2=4

and the product is (2alpha+1)(2beta+1)=4 alpha*beta + 2(alpha+beta) + 1 = 4 * (-2) + 2*(1) +1 = -8 + 2 + 1 = -5. so one of these polynomials is

\Large \boxed{\sf \bf \  \ x^2-4x-5 \ \ }

Thank you.

5 0
3 years ago
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