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Alik [6]
2 years ago
15

A museum charges $12.50 for a one-day youth admission and $17.50 for a one-day adult admission. One Friday, the museum collected

$1485 from a total of 106
youths and adults. How many admissions of each type were sold?
UZE
Mathematics
1 answer:
tatuchka [14]2 years ago
8 0

Answer:

number of youth admissions sold (x) = 74

number of adult admissions sold (y) = 32

Step-by-step explanation:

Let x = number of youth admissions

Let y = number of adult admissions

Given:

  • total number of admissions sold = 106

⇒ x + y = 106

Given:

  • cost of youth admission = $12.50
  • cost of adult admission = $17.50
  • total amount collected = $1485

⇒ 12.5x + 17.5y = 1485

Rewrite  x + y = 106 to make y the subject:

⇒ y = 106 - x

Substitute  y = 106 - x  into 12.5x + 17.5y = 1485 and solve for x:

⇒ 12.5x + 17.5(106 - x) = 1485

⇒ 12.5x + 1855 - 17.5x = 1485

⇒ 5x = 370

⇒ x = 74

Substitute found value of x into y = 106 - x to find y:

⇒ y = 106 - 74

⇒ y = 32

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Answer:

The number of cases prior to the increase is 50.

Step-by-step explanation:

It is given that the number of measles cases increased by 13.6% and the number of cases after increase is 57.

We need to find the number of cases prior to the increase.

Let x be the number of cases prior to the increase.

x + 13.6% of x = 57

x+x\times \frac{13.6}{100}=57

x+0.136x=57

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Divide both the sides by 1.136.

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x=50.176

x\approx 50

Therefore the number of cases prior to the increase is 50.

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Ghella [55]

Answer:

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Step-by-step explanation:

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_____

<em>Additional comment</em>

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Answer:

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