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andrey2020 [161]
3 years ago
6

A science fair poster is a rectangle 3 feet long and 2 feet wide. What is the area of the poster in square inches? Be sure to in

clude the correct unit in your answer.
Mathematics
1 answer:
vredina [299]3 years ago
5 0
Area = length · width
Area = 3ft · 2ft
Area = 6ft²

hope this helps!
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ou draw one card from a​ 52-card deck. Then the card is replaced in the deck and the deck is​ shuffled, and you draw again. Find
julsineya [31]

Answer: Our required probability is \dfrac{1}{52}

Step-by-step explanation:

Since we have given that

Number of cards in a deck = 52

Number of nines = 4

Number of hearts = 13

It is the case of replacement.

Probability of drawing a nine the first time and a hear the second time is given by

\dfrac{4}{52}\times \dfrac{13}{52}\\\\=\dfrac{1}{13}\times \dfrac{1}{4}\\\\=\dfrac{1}{52}

Hence, our required probability is \dfrac{1}{52}

3 0
3 years ago
700 is 10 times as much as blank
creativ13 [48]

700 is 10 times as much as 70 since 70 times 10 equals 700.

70 is the answer

Hope this helps!

8 0
3 years ago
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Nelson and Jamie both want to buy a $250 bicycle.
adelina 88 [10]
Nelson needs to save $114 and Jamie needs $108.
3 0
2 years ago
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Persons having Raynaud's syndrome are apt to suffer a sudden impairment of blood circulation in fingers and toes. In an experime
Citrus2011 [14]

Answer:

There is enough evidence to say that the true average heat output of persons with the syndrmoe differs from the true average heat output of non-sufferers.

Step-by-step explanation:

We have to perform a hypothesis test on the difference between means.

The null and alternative hypothesis are:

H_0: \mu_1-\mu_2=0\\\\H_a: \mu_1-\mu_2

μ1: mean heat output for subjects with the syndrome.

μ2: mean heat output for non-sufferers.

We will use a significance level of 0.05.

The difference between sample means is:

M_d=\bar x_1-\bar x_2=0.63-2.09=-1.46

The standard error is

s_{M_d}=\sqrt{\sigma_1^2/n_1+\sigma_2^2/n_2}=\sqrt{0.3^2/9+0.5^2/9}=\sqrt{ 0.038 } \\\\ s_{M_d}=0.194

The t-statistic is

t=\dfrac{M_d}{s_{M_d}}=\dfrac{-1.46}{0.194}=-7.52

The degrees of freedom are

df=n_1+n_2-2=9+9-2=16

The critical value for a left tailed test at a significance level of 0.05 and 16 degrees of freedom is t=-1.746.

The t-statistic is below the critical value, so it lies in the rejection region.

The null hypothesis is rejected.

There is enough evidence to say that the true average heat output of persons with the syndrmoe differs from the true average heat output of non-sufferers.

5 0
3 years ago
Please help me on this question.
scoundrel [369]

Answer:

f(1)=-48(-\frac{1}{4} )

= 12

f(n)=f(n-1)\:. (-\frac{1}{4} )

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<u>OAmalOHopeO</u>

4 0
2 years ago
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