Ask question

Ask question

All categories

2 years ago

7

Students of Jesus and Mary were divided into 6 teams for a football game. if the school comprises of 3,900 students,how many stu

dents can be found on each team?

1 answer:

gtnhenbr [62]2 years ago

3 0

Answer:

49 students/7 teams= 7 students per team

49/7=7

i hope this work for you

and sory if im wrang

You might be interested in

Help me please show your work I’ll give brainlest.

serious [3.7K]

1. 0.8
2. 3.87298
3. ?
4. ?
5. ?
6. 5
7. True
8. ?
9.

3 0

3 years ago

7.80×10^7/1.0×10^4=?

spin [16.1K]

Answer:780000000000

Step-by-step explanation:7.80×10^7/1.0×10^4=?

7 0

3 years ago

Which linear function is represented by the graph?

Vesnalui [34]

Answer:

f(x)could also be written as y in y= mx+ c

by taking two points we are gonna calculate.

(0,1), (4,-1)

finding m

y*- y'/x*-x'

=1-(-1)/0-4

=2/-4

=-2

now c ( intercept)

take any point

eg. (0,1)

y=mx+c

1=-2×0+c

1=c

equation then equals to

y=-2x+1

f (x) =-2x+1

4 0

3 years ago

Valerie’s meal costs $32.75 and Derek’s meal costs $39.88. Valerie treats Derek by paying for both meals, and leaves a 14%tip. F

boyakko [2]

$32.75+$39.88=$72.63. $72.63+14%=$82.80

5 0

3 years ago

Read 2 more answers

In 2004, a survey on computer crime indicated that 7% of reported unauthorized uses of business Web sites came from inside the c

masya89 [10]

Answer:

a) H0 : P = 0.07

Ha : P ≠ 0.07

b) p -value = 0.1770

Step-by-step explanation:

P = 7% = 0.07

x (result ) = 7 , n = 163

p = x / n = 7 / 163 = 0.043

<u>a) Using a significance level ( ∝ ) of 0.05, estimate the appropriate hypothesis</u>

H0 : P = 0.07

Ha : P ≠ 0.07

conduct a Z- test statistic

Z = ( p - P ) / $\sqrt{\frac{P(1-P)}{n} }$

= ( 0.043 - 0.07 ) / $\sqrt{\frac{P(1-P)}{n} }$ = - 1.35

Critical value ( Z₀.₀₂₅ ) = ± 1.96

<em>we fail to reject H0 given that | z | < Zcritical because there is not enough evidence to conclude that proportion change</em>

<u>b) Determine the p-value of the test </u>

P-value = P ( | Z | > Z )

= 2 * P ( Z < -1.35 )

= 0.1770

The p-value ( 0.1770 ) > ∝ ( 0.05 ) hence we fail to reject H0 ( i.e. the conclusion agrees with part a above )

8 0

3 years ago