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Zielflug [23.3K]
2 years ago
13

What is the mean? 2, 5, 4, 8, 4, 10, 2 TYPE ONLY THE NUMERIC ANSWER

Mathematics
1 answer:
laiz [17]2 years ago
4 0

Answer:

5

Step-by-step explanation:

Do you want to answer my most recent question on my profile? Free 50 points and it's just a one-question survey.

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Given the function with f(3) = 127 and f(1) = 95, determine the rate of change over the interval 1 <3 <3
Sonbull [250]

Answer:

When we have a function f(x) = y.

The rate of change between a and b (where a < b) is:

R = (f(b) - f(a))/(b - a)

In this case:

b = 3

a = 1

f(3) = 127

f(1) = 95

R = (127 - 95)/(3 - 1) = 16

The rate of change in that interval is 16.

3 0
3 years ago
At an annual salary of $55,000 per year, what is the amount of semimonthly paychecks?
Amiraneli [1.4K]
Semi monthly means 2 times per month
assume that pay is at beginning and middle of month (doesn't matter, but  makes it easier for me)

so 12 months
2 times per month
12 times 2=24
divide 55000 by number of months
55,000/24=2291.67

so the amount per paycheck, assuming equally distributed amounts throughout the paychecks, is $2291.67
4 0
3 years ago
A football team loses 3 yards, gains 12 yards, gains 10 yards, and then loses 15 yards. Did the team gain yards or lose yards ov
e-lub [12.9K]

Answer: the answer is 4

Step-by-step explanation:

5 0
3 years ago
PLEASE HELP ASAP!!! I NEED CORRECT ANSWERS ONLY PLEASE!!!
Mila [183]

Answer:

m\angle H = 44.4\°.

Step-by-step explanation:

Given:

In Right Angle Triangle GIH

∠ I = 90°

GI = 7    ....Side opposite to angle H

GH = 10  .... Hypotenuse

To Find:

m∠H = ?

Solution:

In Right Angle Triangle ABC ,Sine Identity,

sin \ H = \frac{Oppsite\  side\  to\  \angle H}{Hypotenuse}

Substituting the values we get;

sin\ H = \frac{7}{10} = 0.7

Now taking sin^{-1} we get;

\angle H = sin^{-1}\ 0.7 = 44.427

rounding to nearest tenth we get.

m\angle H = 44.4\°.

Hence m\angle H = 44.4\°.

6 0
3 years ago
a slitter assembly contains 48 blades five blades are selected at random and evaluated each day for sharpness if any dull blade
son4ous [18]

Answer:

P(at least 1 dull blade)=0.7068

Step-by-step explanation:

I hope this helps.

This is what it's called dependent event probability, with the added condition that at least 1 out of 5 blades picked is dull, because from your selection of 5, you only need one defective to decide on replacing all.

So if you look at this from another perspective, you have only one event that makes it so you don't change the blades: that 5 out 5 blades picked are sharp. You also know that the probability of changing the blades plus the probability of not changing them is equal to 100%, because that involves all the events possible.

P(at least 1 dull blade out of 5)+Probability(no dull blades out of 5)=1

P(at least 1 dull blade)=1-P(no dull blades)

But the event of picking one blade is dependent of the previous picking, meaning there is no chance of picking the same blade twice.

So you have 38/48 on getting a sharp one on your first pick, then 37/47 (since you remove 1 sharp from the possibilities, and 1 from the whole lot), and so on.

Also since are consecutive events, you need to multiply the events.

The probability that the assembly is replaced the first day is:

P(at least 1 dull blade)=1-P(no dull blades)

P(at least 1 dull blade)=1-(\frac{38}{48}* \frac{37}{47} *\frac{36}{46}*\frac{35}{45}*\frac{34}{44})

P(at least 1 dull blade)=1-0.2931

P(at least 1 dull blade)=0.7068

5 0
3 years ago
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