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Rasek [7]
3 years ago
10

A diamond ring costs $1,020 to manufacture and is sold in stores for $1,275. While, a ruby ring that normally sells for $290 is

on sale for $203.
Mathematics
1 answer:
Serggg [28]3 years ago
6 0

Answer:

The 2nd paragraph has the straightforward answer, technically.

This is an example of gross domestic product and today's marketing. When a product is usually paid more money to manufacture than it costs to actually sell. However, the usual difference between manufacturing cost and sales cost is on average is at most 5 - 15% of the manufacturing cost.

The second problem however is just the perfect example of sales and sales tax. The diamond ring is on sale for 30% off in this case, because 290 divided by its percent is equal to 30%, the remaining amount.

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padilas [110]

Answer:

b. -2 and 2

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Answer:

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Kevin Horn is the national sales manager for National Textbooks Inc. He has a sales staff of 40 who visit college professors all
Oduvanchick [21]

Answer:

Following are the solution to the given points:

Step-by-step explanation:

Given values:

38, 40, 41, 45, 48, 48, 50, 50, 51, 51, 52, 52, 53, \\\\54, 55, 55, 55, 56, 56, 57, 59, 59, 59, 62, 62, 62, \\ 63, 64, 65,66, 66, 67, 67, 69, 69, 71, 77, 78, 79, 79

Total staff=40

In point a:

To calculate the median number first we arrange the value into ascending order and then collect the even numbers of calls that were also made. Its average of the middle terms is thus the median.

The midterms =55 and 59 so,

Median = \frac{55+59}{2} = \frac{114}{2}=57

In point b:

First-quarter Q_1 = \frac{1}{4} \text{number of 8th call}

                           =\frac{1}{4} \times  30 th \\\\= 7.5 th

The first quarterlies are 7.5th \  \ that  \ is = (7+0.5)th\ \  term

therefore the multiply of 0.5  by calculating the difference of the 7th and 8th term are:

=0.5 \times 0= 0 \\\\\to Q_1 = 50+0=50 \\\\\to Q_3=\frac{3}{4} \text{number of 8th call} \\\\=\frac{3}{4} \times  30 th \\\\=22.5 \ th  = (22+0.5)th  \ \ term

therefore the it is multiply by the 0.5 for the difference of the 22nd and 23rd term:

= 0.5 \times 1=0.5 \\\\\to Q_3= 63+0.5=63.5

In point c:

First decile D_1 = \frac{1}{18} \text{number of 8th call}

= \frac{1}{10} \times  30 th \\\\= 3rd \ \ term\\\\\to D_1= 41 \\\\\to D_9= \frac{9}{10} \times  8\  th\  call\\\\=\frac{9}{10} \times  30 th \\\\=27th \ \ term\\\\\to D9 = 67

In point d:

quartiles are:

Q_1= 51.25 \\\\Q_3=66

The right answers for the decile are:

D_1=45.3 \\\\ D_9=76.4

As for D) P_{33} = 53.53will be available.

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