Check the picture below.
so is really just a thick trapezoid, or namely a trapezoidal prism 5 inches thick.
so if we just get the area of the trapezoidal face and multiply by the thickness, we'd get it's volume
![\bf \textit{area of a trapezoid}\\\\ A=\cfrac{h(a+b)}{2}~~ \begin{cases} a,b=\stackrel{parallel~sides}{bases}\\ h=height\\[-0.5em] \hrulefill\\ a = 8\\ b = 13\\ h = 6 \end{cases}\implies A=\cfrac{6(8+13)}{2}\implies A=63 \\\\\\ \stackrel{\textit{area of the trapezoidal prism}}{63\cdot 5\implies \stackrel{in^3}{315}}](https://tex.z-dn.net/?f=%5Cbf%20%5Ctextit%7Barea%20of%20a%20trapezoid%7D%5C%5C%5C%5C%20A%3D%5Ccfrac%7Bh%28a%2Bb%29%7D%7B2%7D~~%20%5Cbegin%7Bcases%7D%20a%2Cb%3D%5Cstackrel%7Bparallel~sides%7D%7Bbases%7D%5C%5C%20h%3Dheight%5C%5C%5B-0.5em%5D%20%5Chrulefill%5C%5C%20a%20%3D%208%5C%5C%20b%20%3D%2013%5C%5C%20h%20%3D%206%20%5Cend%7Bcases%7D%5Cimplies%20A%3D%5Ccfrac%7B6%288%2B13%29%7D%7B2%7D%5Cimplies%20A%3D63%20%5C%5C%5C%5C%5C%5C%20%5Cstackrel%7B%5Ctextit%7Barea%20of%20the%20trapezoidal%20prism%7D%7D%7B63%5Ccdot%205%5Cimplies%20%5Cstackrel%7Bin%5E3%7D%7B315%7D%7D)
<span>The area of the square is 25/36 feet.
Area of a square = length * width
Area of a square = 5/6 feet * 5/6 feet
Area of a square = 25/36 feet</span>
Answer:
17 in.
Step-by-step explanation:
There are two same angles shown, so two sides are equal. We can form an equation x+4=4x+1. Solution is x=1, then both unknown sides are 5 in. long. Given all side lengths we add them 7+5+5+15 getting the perimeter.