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jarptica [38.1K]
3 years ago
8

a big cruise ship dropped anchor off the Caribbean island of antigua. the heavy anchor dropped into the water at a rate of 2.5 m

eters per second after 45 seconds the anchor was 40 meters below the waters surface. from what height above the water surface was the anchor released? how long did it take the anchor the reach the water surface?
Mathematics
1 answer:
AysviL [449]3 years ago
6 0

Falling at the rate of 2.5 m/s for 45 seconds, the anchor fell

                                     (2.5 m/s) x (45 s)  =  112.5 meters .

If it wound up only 40 meters underwater, then it must have fallen

                                      (112.5 m  -  40 m)  =  72.5 meters

from its storage position on the big cruise ship, 
before it ever reached the water.

Since it was falling at the rate of  2.5 m/s, it took

                                     (72.5 m) / (2.5 m/s)  =  29 seconds

to get down to the water surface after it started dropping.

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Ten(10) adults and 3 children attend a local concert for $59. Four(4) adults and 3
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Concert tickets cost $15 for general admission, but only $9 with a student ID. Ticket sales total $450. Write and graph an equat
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The equation that models the situation is 15x + 9y = 450

The x-intercept is (30, 0) and the y-intercept is (0, 50)

Given the following parameters:

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Given that the total sales is $450, the equation that models this situation will be expressed as:

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where:

x is the those that admitted generally

y are those with student ID

<u />

<u>Get the x-intercept.</u>

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Thee x-intercept is (30, 0)

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Learn more on intercepts here: brainly.com/question/24212383

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