2 years ago

1 + 1 + 1 in standard form

1 answer:

inn [45]2 years ago

6 0

Answer: 3

Step-by-step explanation:

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Answer:

The hourly pay for the lifeguards in 2001 was of $6.31.

Step-by-step explanation:

The hourly pay, in dollars, in t years after 1995, is given by the following equation:

$P(t) = 5.60(1.02)^{t}$

What was the hourly pay for the lifeguards in 2,001?

2001 is 2001 - 1995 = 6 years after 1995. So this is P(6).

$P(t) = 5.60(1.02)^{t}$

$P(6) = 5.60(1.02)^{6} = 6.31$

The hourly pay for the lifeguards in 2001 was of $6.31.

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skelet666 [1.2K]

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3 years ago

Mekhanik [1.2K]

239.99 x 75%(75/100) ~ $180
$180 x 90%(90/100) = $162

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3 years ago

Gnesinka [82]

3, 6, 9, 12, 15
I did what you asked

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3 years ago

mojhsa [17]

Answer:

Step-by-step explanation:

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