If you are graphing quadratic equations of the type
ax^2 + bx + c = 0
The equation will look like a "U" <span>if "a" is positive </span>or it will look like an upside-down "U" <span>if "a" is negative </span>
Answer: option C
Step-by-step explanation:
The diagram of the triangle is shown in the attached photo. The triangle is a right angle triangle ABC
Assuming the given angle is #,
Recalling the trigonometric ratio,
tan # = opposite / adjacent
If tan # = 4, it means
opposite / adjacent = 4/1
Therefore, opposite = 4 and adjacent = 1
Applying Pythagoras theorem,
Hypotenuse^2 = opposite ^2 + adjacent ^2
Hypotenuse = AC
Opposite = 4
Adjacent = 1
AC^2 = 4^2 + 1^2 = 17
AC = ± √17
To determine cos #, we would apply another trigonometric ratio,
Cos# = adjacent /hypotenuse
Cos# = 1/±√17
Cos # =-1 /√17 or 1/√17
I think it’s D or maybe just maybe it’s will have to be B
Standard form is another way of saying slope-intercept form. The equation you have there is in point-slope form, so we must convert this to slope-intercept form to get our final answer.
In point-slope form (y - k = m(x - h)) k is the y-value, h is the x-value, and m is the slope. All we must do is change your equation's form into standard form, or slope-intercept form which looks like this: (y = mx + b), where m is the slope and b is the y-intercept.
Convert this equation y + 1 = 2/3(x + 4) into standard/slope-intercept form.
y + 1 = 2/3(x + 4)
y + 1 = 2/3x + 2.666 Here we multiplied 2/3 by x and 4 since x + 4 is in parenthesis next to 2/3.
y + 1 - 1 = 2/3x + 2 2/3 - 1 Now we want to get y by itself so the form will look like y = mx + b, so we subtract the 1 from both sides of the equation. (2 2/3 is a mixed fraction that is equal to 2/3*4.)
y = 2/3x + 1 2/3
This is our final answer since it is in the standard, or slope-intercept form. Hope this made sense! If you have any questions please ask.
Answer:
The quantity of acid in the solution is 47.1 ml
Step-by-step explanation:
Given as :
The quantity of solution of acid and water = 357 millimeters
The percentage of acid in the solution = 13.2 %
Let the quantity of acid in the solution = x ml
<u>So, According to question </u>
13.2 % of the total quantity of acid in the solution = x
I.e x = 13.2 % × 357
Or, x =
× 357
Or, x = 0.132 × 357
∴ x = 47.124 millimeters
So , The quantity of acid = 47.1 ml
Hence The quantity of acid in the solution is 47.124 ml Answer