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LiRa [457]
2 years ago
9

In a certain isosceles triangle, the base is $1\frac 12$ times as long as each leg and the perimeter is $63. $ how long is the b

ase?
SAT
1 answer:
V125BC [204]2 years ago
7 0

The length of the base of the isosceles triangle is: 27 units long.

<h3>What is an isosceles Triangle?</h3>

A triangle with two equal legs and a base is called an isosceles triangle.

Thus:

Let x represent the length of each of the equal legs of the isosceles triangle.

Therefore:

The length of the base = 1 1/2(x) = 1.5x units

Perimeter = 63

Therefore:

x + x + 1.5x = 63

3.5x = 63

x = 63/3.5

x = 18

The length of the base = 1.5x units

Plug in the value of x

The length of the base = 1.5(18) = 27 units

Therefore, the length of the base of the isosceles triangle is: 27 units long.

Learn more about isosceles triangle on:

brainly.com/question/11884412

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