Question

Find the values of P for which the quadratic equation 4x²+px+3=0?​

Answer 1

Correct Questions :-

Find the values of P for which the quadratic equation 4x²+px+3=0 , provided that roots are equal or discriminant is zero .

Solution:-

Let us Consider a quadratic equation αx² + βx + c = 0, then nature of roots of quadratic equation depends upon Discriminant (D) of the quadratic equation.

For equal roots

• D = 0

$\quad\green{ \underline { \boxed{ \sf{Discriminant, D = β² - 4αc}}}}$

So,

$\sf{ β² - 4αc = 0}$

Here,

• α = 4
• β = p
• c = 3

Now,

$\begin{gathered}\implies\quad \sf p²- 4 \times 4 \times 3 =0 \end{gathered}$

$\begin{gathered}\implies\quad \sf p²- 48 =0 \end{gathered}$

$\begin{gathered}\implies\quad \sf p²=48\end{gathered}$

$\begin{gathered}\implies\quad \sf p=±\sqrt{48}\end{gathered}$

$\begin{gathered}\implies\quad \sf p=±\sqrt{2 \times 2 \times 2 \times 2 \times 3} \end{gathered}$

$\begin{gathered}\implies\quad \sf p=± 2\times 2\sqrt{ 3 }\end{gathered}$

$\begin{gathered}\implies\quad \boxed{\sf{p=±4\sqrt{ 3 }}}\end{gathered}$

Thus, the values of P for which the quadratic equation 4x²+px+3=0 are-

4√3 and -4√3.