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sleet_krkn [62]
3 years ago
14

What purpose does encryption on the internet serve? Why is it so important?

Computers and Technology
1 answer:
Ivanshal [37]3 years ago
7 0

Answer:

it keeps cybercriminals from stealing private information

Explanation:

hope this helps

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You are given a 11-bit floating point representation with 1-sign bit, 3 bits for the exponent, and 7-bits for the mantissa. Expr
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Answer:

Sign Bit = 0 (for Positive number)

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Mantissa = 1111 11 0 (7 bits for mantissa)

the answer is

<em>sign bit -   Exponent -     Mantissa</em>

The representation of 15.75 in binary in 11 bits is given as

<em>0 - 111 - 1111 11 0</em>

<em></em>

Explanation:

Given data  

15.75 in decimal

calculate it in binary.

1.          

15/2 = 7 (Quotient)   and 1 (remainder)

7/2 = 3 (Quotient)     and 1 (remainder)

3/2 = 1 (Quotient)     and 1 (remainder)

by arranging them in order

<em>15 in decimal = 1111 in binary</em>

<em />

<em>2.</em>

<em />

<em>Now convert 0.75 by dividing 2 , </em>

multiplying = integer + fractional part;

1) 0.75 × 2 =  1.5 = <em><u>1</u></em> + 0.5;

2) 0.5 × 2 = 1= <u><em>1 </em></u>+ 0;

<em>so</em>

<em>0.75 in decimal = 0.11 in binary</em>

<em />

<em>3. </em>Because it is the 15.75 is positive number so we add 0 in extreme right as

<em> 15.75 =  0  1111 . 11</em>

<em>4.  Now making it normalize as by moving point</em>

<em />

0.1111 11 x 2^4

so exponent is 4.

<em />

<em>5. As exponent is 3 bits </em>

exponent + 2^ (No of bits-1) -1

4+ 2 ^ (3-1) - 1 =  4+4 -1 = 8-1 = 7

Now divide 7 by 2

<em>so </em>

7/2 = 3 (Quotient)     and 1 (remainder)

3/2 = 1 (Quotient)     and 1 (remainder)

<em>so exponent in bits is 111</em>

<em>6. Now calculate mantissa</em>

Just remove the point from 0.1111 11 as 1111 11

Now add rest of the bits 0 at right side

mantissa = 1111 11 0

<em />

<em />

<em></em>

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