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3 years ago

Write a program that prompts the user to enter an oligonucleotide sequence, such as TATGAGCCCGTA.

Computers and Technology

1 answer:

Alexxx [7]3 years ago

7 0

Answer:

Explanation:

The following code is written in Python. It continues looping and asking the user for an oligonucleotide sequence and as long as it is valid it outputs the reverse complement of the sequence. Otherwise it exits the loop

letters = {'A', 'C', 'G', 'T'}

reloop = True

while reloop:

sequence = input("Enter oligonucleotide sequence: ")

for x in sequence:

if x not in letters:

reloop = False;

break

if reloop == False:

break

newSequence = ""

for x in sequence:

if x == 'A':

newSequence += 'T'

elif x == 'T':

newSequence += 'A'

elif x == 'C':

newSequence += 'G'

elif x == 'G':

newSequence += 'C'

print("Reverse Complement: " + newSequence)

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2.8 Code Practice: Question 1

-BARSIC- [3]

Answer:

The program to this question can be given as:

Program:

#include <stdio.h> //define header file

int main() //define main method.

{

int a1,b1,c1; //define variable

printf("Enter three numbers:\n"); //message

scanf("%d",&a1); //input numbers.

scanf("%d",&b1);//input numbers.

scanf("%d",&c1);//input numbers.

if (a1>b1) //check condition

{

//check condition

if(a1>c1)//inner if block

{

printf("The largest number: %d", a1); //message

}

else //inner else block

{

printf("The largest number: %d", c1);//message

}

else //else block

{

//check condition

if(b1>c1) //inner if block.

{

printf("The largest number: %d", b1);//message

}

else //else block

{

printf("The largest number: %d",c1);//message

}

return 0; //return 0.

}

Output:

Enter three numbers:

The largest number: 44

Explanation:

The description of the above program can be given as:

In the C language program firstly we define the header file. Then we define the main function. In the main function, we define three variables that are "a1, b1 and c1". In this variable, we take input from the user.
Then we define the conditional statements. In the if block we check if the value of a1 is greater then the value of b1 if this condition is true so we use another condition that if the value of a1 is greater then the value of c1. so, it will print the largest value. If the above condition is not true then it will go to else section.
In the else part we check the condition that if the value of b1 is greater then the value of c1. if it is true it will print the largest number value.

4 0

3 years ago

Read 2 more answers

A real estate office handles 50 apartment units. When the rent is $600 per month, all the units are occupied. However, for each

Vesnalui [34]

Answer:

452

Explanation:

7 0

3 years ago

After this week im gonna be moderator who ever needs help let me know

Sav [38]

Answer:

Explanation:

thanks, for offering help through here. Have a nice day.

4 0

3 years ago

Which visual aid should Emil use to compare and contrast the political systems in three countries?

BaLLatris [955]

A vent diagram. It helps to outline the differences and the similarities between the three countries

5 0

3 years ago

How many different messages can be transmitted in n microseconds using three different signals if one signal requires 1 microsec

SIZIF [17.4K]

Answer:

a_{n} = 2/3 . 2^n + 1/3 . (-1)^n

Explanation:

Let a_{n} represents number of the message that can transmitted in <em>n </em>microsecond using three of different signals.

One signal requires one microsecond for transmittal: a_{n}-1

Another signal requires two microseconds for transmittal: a_{n}-2

The last signal requires two microseconds for transmittal: a_{n}-2

a_{n}= a_{n-1} + a_{n-2} + a_{n-2} = a_{n-1} + 2a_{n-2}, n ≥ 2

In 0 microseconds. exactly 1 message can be sent: the empty message.

a_{0}= 1

In 1 microsecond. exactly 1 message can be sent (using the one signal of one microseconds:

a_{0}= 1

2- Roots Characteristic equation

Let a_{n} = r^2, a_{n-1}=r and a_{n-2}= 1

r^2 = r+2

r^2 - r - 2 =0 Subtract r+6 from each side

(r - 2)(n+1)=0 Factorize

r - 2 = 0 or r +1 = 0 Zero product property

r = 2 or r = -1 Solve each equation

Solution recurrence relation

The solution of the recurrence relation is then of the form a_{1} = a_{1 r^n 1} + a_{2 r^n 2} with r_{1} and r_{2} the roots of the characteristic equation.

a_{n} =a_{1} . 2^n + a_{2}.(-1)"

Initial conditions :

1 = a_{0} = a_{1} + a_{2}

1 = a_{1} = 2a_{1} - a_{2}

Add the previous two equations

2 = 3a_{1}

2/3 = a_{1}

Determine a_{2} from 1 = a_{1} + a_{2} and a_{1} = 2/3

a_{2} = 1 - a_{1} = 1 - 2 / 3 = 1/3

Thus, the solution of recursion relation is a_{n} = 2/3 . 2^n + 1/3 . (-1)^n

6 0

3 years ago