Answer:
Fraction
Step-by-step explanation:
Answer:
y=21.14
Step-by-step explanation:
x=6 because after 6 weeks
y= 3.27(6)+ 1.52
y=19.62 + 1.52
y=21.14
Answer:
![\boxed{\sf \ \ \ x=2, \ \ y =1 \ \ \ }](https://tex.z-dn.net/?f=%5Cboxed%7B%5Csf%20%5C%20%5C%20%5C%20x%3D2%2C%20%5C%20%5C%20y%20%3D1%20%5C%20%5C%20%5C%20%7D)
Step-by-step explanation:
Hello,
Pls post the full question next time so that we can make sure what is expected.
I assume that you want to solve for (x,y)
(1) 2x + 3y = 7
(2) 3x + 2y = 8
2*(2)-3*(1) gives
2*3x + 2*2y - 3*2x - 3*3y = 2*8 - 3*7 = 16 - 21 = -5
6x - 6x + 4y -9y = -5
-5y=-5
y = 1
and we can replace in (1)
2x + 3*1 = 7
2x = 7 - 3 = 4
x = 2
hope this helps
Your answer is (3,1) because if you graph the line that is the on off the line the other follow through
Answer:
The upper endpoint of the 99% confidence interval for population proportion is 0.13.
Step-by-step explanation:
The confidence interval for population proportion is:
![CI=\hat p\pm z_{\alpha /2}\sqrt{\frac{\hat p(1-\hat p)}{n}}](https://tex.z-dn.net/?f=CI%3D%5Chat%20p%5Cpm%20z_%7B%5Calpha%20%2F2%7D%5Csqrt%7B%5Cfrac%7B%5Chat%20p%281-%5Chat%20p%29%7D%7Bn%7D%7D)
<u>Given:</u>
<em>n</em> = 1000
= 0.102
![z_{\alpha /2}=z_{0.01/2}=z_{0.005}=2.58](https://tex.z-dn.net/?f=z_%7B%5Calpha%20%2F2%7D%3Dz_%7B0.01%2F2%7D%3Dz_%7B0.005%7D%3D2.58)
*Use the standard normal table for the critical value.
Compute the 99% confidence interval for population proportion as follows:
![CI=\hat p\pm z_{\alpha /2}\sqrt{\frac{\hat p(1-\hat p)}{n}}\\=0.102\pm 2.58\times\sqrt{\frac{0.102(1-0.102)}{1000}}\\=0.102\pm0.0248\\=(0.0772, 0.1268)\\\approx (0.08, 0.13)](https://tex.z-dn.net/?f=CI%3D%5Chat%20p%5Cpm%20z_%7B%5Calpha%20%2F2%7D%5Csqrt%7B%5Cfrac%7B%5Chat%20p%281-%5Chat%20p%29%7D%7Bn%7D%7D%5C%5C%3D0.102%5Cpm%202.58%5Ctimes%5Csqrt%7B%5Cfrac%7B0.102%281-0.102%29%7D%7B1000%7D%7D%5C%5C%3D0.102%5Cpm0.0248%5C%5C%3D%280.0772%2C%200.1268%29%5C%5C%5Capprox%20%280.08%2C%200.13%29)
Thus, the upper limit of the 99% confidence interval for population proportion is 0.13.