Looking at this problem in terms of geometry makes it easier than trying to think of it algebraically.
If you want the largest possible x+y, it's equivalent to finding a rectangle with width x and length y that has the largest perimeter.
If you want the smallest possible x+y, it's equivalent to finding the rectangle with the smallest perimeter.
However, the area x*y must be constant and = 100.
We know that a square has the smallest perimeter to area ratio. This means that the smallest perimeter rectangle with area 100 is a square with side length 10. For this square, x+y = 20.
We also know that the further the rectangle stretches, the larger its perimeter to area ratio becomes. This means that a rectangle with side lengths 100 and 1 with an area of 100 has the largest perimeter. For this rectangle, x+y = 101.
So, the difference between the max and min values of x+y = 101 - 20 = 81.
Answer:
b. -x^2 + 50 = 25
c. |2x| = 10
d. x < 0
e. 2x < 10
Step-by-step explanation:
x = -5
-(-5)² + 50
-25 + 50 = 25
|2(-5)| = |-10| = 10
-5 < 0
2(-5) = -10 < 10
Answer:
Simplify the expression.
0.02977742
Step-by-step explanation:
i think i hope its right
Answer:
Step-by-step explanation:
Distance : 
Midpoint :
x (m) = (2+9)/2 = 11/2
y (m) = (-14-9)/2 = -23/2
M (11/2, -23/2)
Ummmm I’m not sure but ya
