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ryzh [129]
2 years ago
10

Can someone give me a simple topic for a website please be creative make it simple! and fun for brainliest

Computers and Technology
1 answer:
forsale [732]2 years ago
3 0

Answer:

hmm you could talk about your dailylife , or stuff you like to do etc do what you like <3 , if you like art you could do that to!

Explanation:

Can someone give me a simple topic for a website? please be creative make it simple! and fun for brainliest

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epic poem - long narrative poem about heroic deeds about pharrell williams of the happy song please help i need the right answer
Naddik [55]

"Happy" is a song written, produced, and performed by American singer Pharrell Williams, released as the first and only single from the soundtrack album for the film Despicable Me 2 (2013). The song was first released on November 21, 2013, alongside a long-form music video. The song was reissued on December 16, 2013, by Back Lot Music under exclusive license to Columbia Records, a division of Sony Music.[1] The song also served as the lead single from Williams' second studio album, Girl (2014).

"Happy" is an uptempo soul and neo soul song on which Williams's falsetto voice has been compared to Curtis Mayfield by critics. The song has been highly successful, peaking at No. 1 in the United States, United Kingdom, Canada, Ireland, New Zealand, and 19 other countries. It was the best-selling song of 2014 in the United States with 6.45 million copies sold for the year,[3] as well as in the United Kingdom with 1.5 million copies sold for the year.[4] It reached No. 1 in the UK on a record-setting three separate occasions and became the most downloaded song of all time in the UK in September 2014;[5] it is the eighth highest-selling single of all time in the country.[6] It was nominated for an Academy Award for Best Original Song. A live rendition of the song won the Grammy Award for Best Pop Solo Performance at the 57th Annual Grammy Awards.

The music video for "Happy" was nominated for Best Male Video and Video of the Year at the 2014 MTV Video Music Awards. It also won the Grammy Award for Best Music Video at the 57th Annual Grammy Awards.[7][8] The song was Billboard's number-one single for 2014.

"Happy" was the most successful song of 2014, with 13.9 million units (sales plus equivalent streams) worldwide

7 0
3 years ago
Program 7 - Circle You write ALL the code, then run it - Produce the correct output. Turn in code and screen print of successful
fgiga [73]

Answer:

Here is the Circle class:

public class Circle {   // class definition

private int radius;    // private data member of type int of class Circle named radius that stores the value of radius

public Circle(int r) {   // parameterized constructor of class Circle that takes radius as argument

 radius = r;  }    // sets value of radius as r

public int getRadius() {   // accessor method to get the value of radius

 return radius;  }   // returns the current value of radius

public int Diameter() {   // method to compute diameter of a circle

 return radius * 2;  }   // multiply radius value by 2 to compute diameter of Circle

 

public double Area() {   // method to compute area of a circle

 return Math.PI  * Math.pow(radius, 2);   }   //the formula of area is

π x radius² where value of π is get using Math.PI

 

 public double Circumference() {   // // method to compute circumference of a circle

 return 2* Math.PI * radius;   }   }  //the formula of circumference is

2 x π x radius where value of π is get using Math.PI

Explanation:

Here is the Main class:

import java.util.Scanner;  //to accept input from user

public class Main {  //definition of Main class

public static void main(String[] args) {  //start of main method

   

    Scanner scanner = new Scanner (System.in);  //creates Scanner object to take input from user

    System.out.println("Enter radius: ");  //prompts user to enter radius

    int r = scanner.nextInt();  //reads the value of radius from user

 Circle c = new Circle(r);  // calls Constructor of Circle passing r as argument to it using the object c of class Circle

 

    if(c.getRadius()<=0){  //calls getRadius method to get current value of radius using objec and checks if this value (input value of r ) is less than or equal to 0

        System.out.println("Error!");   }  //when above if condition evaluates to true then print this Error! message

    else {  //if the value of radius is greater than 0

System.out.println("the radius of this Circle is: " +c.getRadius());  //calls getRadius method to return current value of r (input value by user)

System.out.println("the diameter of this Circle  is: " + c.Diameter());  //calls Diameter method to compute the diameter of Circle and display the result on output screen

System.out.printf("the circumference of this Circle  is: %.2f", c.Circumference());  //calls Circumference method to compute the Circumference of Circle and display the result on output screen

System.out.println();  //prints a line

System.out.printf("the Area of this Circle  is: %.2f", c.Area()); } }  }

//calls Area method to compute the Area of Circle and display the result on output screen

The program and its output is attached.

7 0
3 years ago
All HTML5 webpages must begin with the HTML element _____.
Paul [167]

Answer:

yes, an HTML webpage must begin with an HTML element

Explanation:

<HTML> <!-- Website Content --> </HTML>

3 0
2 years ago
A signal travels from point A to point B. At point A, the signal power is 100 W. At point B, the power is 90 W. What is the atte
11Alexandr11 [23.1K]

Answer:

Attenuation = 0.458\ db

Explanation:

Given

Power at point A = 100W

Power at point B = 90W

Required

Determine the attenuation in decibels

Attenuation is calculated using the following formula

Attenuation = 10Log_{10}\frac{P_s}{P_d}

Where P_s = Power\ Input and P_d  = Power\ output

P_s = 100W

P_d = 90W

Substitute these values in the given formula

Attenuation = 10Log_{10}\frac{P_s}{P_d}

Attenuation = 10Log_{10}\frac{100}{90}

Attenuation = 10 * 0.04575749056

Attenuation = 0.4575749056

Attenuation = 0.458\ db <em>(Approximated)</em>

7 0
3 years ago
What is a killer app??
mars1129 [50]
Application of a new technology and is much superior to rival products
6 0
3 years ago
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