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Mazyrski [523]
3 years ago
10

A computer's hard disk drive holds 8 x 10^10 bytes of information. If Jill buys an extra memory stick that holds 5.1 X 10^8 byte

s of information, how much memory will the computer hold all together?
Computers and Technology
1 answer:
denis-greek [22]3 years ago
8 0

Answer:

The computer will store 8.05 *10^10 bytes of information.

Explanation:

This is the same as saying that the computer will now have 80.51 Gigabytes ( 1gb = 1.000.000.000 bytes) of storage. In this case, the number is represented in its decimal form, and the previous one is displayed in Scientific Notation.

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Answer:

The program in C++ is as follows:

#include <iostream>

#include <iomanip>

using namespace std;

int main(){

   int cars;

   cin>>cars;

   double weights[cars];

   double total = 0;

   for(int i = 0; i<cars;i++){

       cin>>weights[i];

       total+=weights[i];    }

   double avg = total/cars;

   for(int i = 0; i<cars;i++){

       cout<<fixed<<setprecision(1)<<avg-weights[i]<<endl;    }

   return 0;

}

Explanation:

This declares the number of cars as integers

   int cars;

This gets input for the number of cars

   cin>>cars;

This declares the weight of the cars as an array of double datatype

   double weights[cars];

This initializes the total weights to 0

   double total = 0;

This iterates through the number of cars

   for(int i = 0; i<cars;i++){

This gets input for each weight

       cin>>weights[i];

This adds up the total weight

       total+=weights[i];    }

This calculates the average weights

   double avg = total/cars;

This iterates through the number of cars

   for(int i = 0; i<cars;i++){

This prints how much weight to be added or subtracted

       cout<<fixed<<setprecision(1)<<avg-weights[i]<<endl;    }

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Answer:

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