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2 years ago

What is the slope of a line parallel 18x+15y=90

Mathematics

2 answers:

luda_lava [24]2 years ago

5 0

Answer:

-6/5

Step-by-step explanation:

Get y by itself to get the slope. So 18x+15y=90. Move 18x to the other side of the equation. Now you have 15y=-18x+90. Divide both sides by 15 to get y by itself. Now it's y= -18/15x + 6. Reduce -18/15 to the simplest fraction. You have y= -6/5x+6. Any number can replace the 6 in the equation to give you a parallel line...it's the slope that makes it parallel, not the y intercept. So y= -6/5x+10 or y=- -6/5x-1 would satisfy your parallel slope equation.

Mrrafil [7]2 years ago

3 0

Answer:

$\displaystyle -1\frac{1}{5}$

Step-by-step explanation:

$\displaystyle 18x + 15y = 90 \hookrightarrow \frac{15y}{15} = \frac{-18x + 90}{15} \\ \\ \boxed{y = -1\frac{1}{5}x + 6}$

Parallel equations have SIMILAR <em>RATE OF CHANGES</em> [<em>SLOPES</em>], so −1⅕ remains as is.

I am joyous to assist you at any time.

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If PQ bisects Angle RPS and measure of angle RPS = 120°, find p and measure of angle RPQ.

Ghella [55]

Answer:

p = 6; RPQ = 60 degrees

Step-by-step explanation:

Because RPS is 120 degrees and it is bisected by PQ (cut into 2 equal parts), we can determine that both sides are 60 degrees. Set the expression 5p+30 equal to 60 to find the value of p.

5p + 30 = 60

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So now you have determined that p = 6, and the measure of RPQ is 60 degrees.

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3 years ago

-x^(2)-12=-87<br><br> Please explain your answer, and how I make the x positive

spayn [35]

Solve for x over the real numbers:
-x^2 - 12 = -87
Add 12 to both sides:
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3 years ago

Melissa Costouras obtains a $3,000 loan for darkroom equipment. She makes six monthly payments of $511.18. Determine the APR.

nasty-shy [4]

Using the simple interest formula, it is found that the APR for the loan is of 4.472%.

<h3>What is the simple interest formula and when it is used?</h3>

Simple interest is used when there is a single compounding per time period.

The amount of money after t years in is modeled by:

$A(t) = A(0)(1 + rt)$

In which:

A(0) is the initial amount.

r is the interest rate, as a decimal.

The parameters for this problem are:

A(t) = 6 x 511.18 = 3067.08, A(0) = 3000, t = 0.5.

We solve the equation for r to find the APR.

$A(t) = A(0)(1 + rt)$

$3067.08 = 3000(1 + 0.5r)$

$1 + 0.5r = \frac{3067.08}{3000}$

1 + 0.5r = 1.02236

r = (1.02236 - 1)/0.5

r = 0.04472.

More can be learned about simple interest at brainly.com/question/25296782

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