Its 15 markers, at least i would assume
We know:x^2+y^2+x−6y+9=0So, we complete the square as such:x^2+y^2+x−6y+9=x^2+x+y^2−6y+9=(x+1/2)^2+(y−3)^2=(1/2)^2=1/4
Answer:
Distance LM = 5.20 unit (Approx.)
Step-by-step explanation:
Given coordinates;
L(1, 4, 7) and M(2, 9, 8)
Find:
Distance LM
Computation:
Distance between three-dimensional plane = √(x2 - x1)² + (y2 - y1)² + (z2 - z1)²
Distance LM = √(2 - 1)² + (9 - 4)² + (8 - 7)²
Distance LM = √(1)² + (5)² + (1)²
Distance LM = √1 + 25 + 1
Distance LM = √27
Distance LM = 3√3 unit
Distance LM = 3(1.732)
Distance LM = 5.196
Distance LM = 5.20 unit (Approx.)
Answer:
27 L
Step-by-step explanation:
To find 12.5% of 24, move the decimal all the way to the left and multiply 24 by 0.125. You get 3, which is how much was added to the original volume.
24 + 3 = 27, which is the new volume.
Answer:
The fraction of the area of ACIG represented by the shaped region is 7/18
Step-by-step explanation:
see the attached figure to better understand the problem
step 1
In the square ABED find the length side of the square
we know that
AB=BE=ED=AD
The area of s square is

where b is the length side of the square
we have

substitute


therefore

step 2
Find the area of ACIG
The area of rectangle ACIG is equal to

substitute the given values

step 3
Find the area of shaded rectangle DEHG
The area of rectangle DEHG is equal to

we have 

substitute
step 4
Find the area of shaded rectangle BCFE
The area of rectangle BCFE is equal to

we have


substitute

step 5
sum the shaded areas

step 6
Divide the area of of the shaded region by the area of ACIG

Simplify
Divide by 5 both numerator and denominator

therefore
The fraction of the area of ACIG represented by the shaped region is 7/18