Answer:
Let O be the center of a circle whose radius is r cm , in which AB= 14 cm long
cord is at a distanceof 24 cm from O. Draw a perpendicular OD on AB , thus ,
OD= 24 cm.
In right angled triangle. ODB
OB^2 = OD^2+ DB^2
r^2 =(24)^2+(AB/2)^2 = 576+(14/2)^2
r^2 = 576+ 49=625
r = √625. =25 cm. Answer.
The solution for proving the identity is as follows:
sin(2A) = sin(A + A)
As sin(a + b) = sinacosb + sinbcosa,
<span>sin(A + A) = sinAcosA + sinAcosA
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<span>Therefore, sin(2A) = 2sinAcosA
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Answer:
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Step-by-step explanation:
The answer is D because you have to divide 812 by 25.3
Answer:

Step-by-step explanation:
Corresponding angles of two parallel lines are always equal. The angle on "top" of
corresponds with the angle marked as
. Therefore, its measure must also be
.
Since these two angles form one side of a line which has 180 degrees, we have the following equation:

Combine like terms:

Subtract 15 from both sides:

Divide both sides by 3:
