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garri49 [273]
3 years ago
5

Find the area of a triangle whose vertices have the coordinates (-1,1) (-1,5) (4,1)

Mathematics
1 answer:
Alekssandra [29.7K]3 years ago
7 0

The triangle that forms is a right-angled triangle. To work out the area, you just do the base × height, all divided by 2.

Therefore, you do 5 (the base) × 4 (the height) and you get 20.

Then you divide by 2 to finish the equation and you should find that the total area of the triangle is 10 units² (20 ÷ 2 = 10).

Hope that helps :)

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When n = 3, which of the expressions below will be greater than 50? Select all that apply. A) (8n2÷9)⋅7 B) 2n2⋅3 –4n C) 4n2–6n+1
True [87]

Answer:

<u><em>A</em></u>

Step-by-step explanation:

<u>a)</u>

<u></u>(8(3)^{2} / 9) * 7<u></u>

<u>8(9) / 9 = 8 x 7 = 56</u>

b)

2(3)^{2} * 3 - 4(3)

2(9) * 3 - 12

18 * 3 = 54 - 12 = 42

c)

4(3)^{2} - 6(3) + 12

4(9) - 18 + 12

36 - 18 = 18 + 12 = 30

d)

7(3) + (3 * 8)

21 + 24 = 45

5 0
3 years ago
The base of a rectangular prism has an area of 26.25, and the height of the prism is 4.5. What is the volume? Round to the neare
kramer

The right answer is 118.

Look at the attached picture

Hope it will help you....

Good luck on your assignment.

4 0
3 years ago
Read 2 more answers
1+secA/sec A = sin^2 A / 1-cos A​
Fofino [41]

Answer:  see proof below

<u>Step-by-step explanation:</u>

\dfrac{1+\sec A}{\sec A}=\dfrac{\sin^2 A}{1-\cos A}

Use the following Identities:

sec Ф = 1/cos Ф

cos² Ф + sin² Ф = 1

<u>Proof LHS → RHS</u>

\text{LHS:}\qquad \qquad \dfrac{1+\sec A}{\sec A}

\text{Identity:}\qquad \qquad \dfrac{1+\frac{1}{\cos A}}{\frac{1}{\cos A}}

\text{Simplify:}\qquad \qquad \dfrac{\frac{\cos A+1}{\cos A}}{\frac{1}{\cos A}}\\\\\\.\qquad \qquad \qquad =\dfrac{1+\cos A}{1}

\text{Multiply:}\qquad \qquad \dfrac{1+\cos A}{1}\cdot \bigg(\dfrac{1-\cos A}{1-\cos A}\bigg)\\\\\\.\qquad \qquad \qquad =\dfrac{1-\cos^2 A}{1-\cos A}

\text{Identity:}\qquad \qquad \dfrac{\sin^2 A}{1-\cos A}

\text{LHS = RHS:}\quad \dfrac{\sin^2 A}{1-\cos A}=\dfrac{\sin^2 A}{1-\cos A}\quad \checkmark

3 0
3 years ago
The range for a list of numbers is 7. the smallest value is 4. what is the largest value in the list
Katena32 [7]

Answer:

7

Step-by-step explanation:

8 0
2 years ago
Can anyone help with this?!?!
Gnom [1K]
Since y=5 is an asymptote, it means that y will approach 5 but never be 5. So you use (. Then, you see the function increasing from the asymptote so it would be (5, infinity) Choice C
5 0
3 years ago
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