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Damm [24]
3 years ago
10

What is the 3 correct answers?

Mathematics
2 answers:
Bumek [7]3 years ago
6 0

Here is notation

  • If a function be ax^2+bx+c
  • c is the y intercept

Now our answers are

  1. -5
  2. 8
  3. -11
Alona [7]3 years ago
4 0

The given functions are written in the standard form:

\tt \to \: ax ^{2}  + bx + c = 0

Where,

  • C is the y-intercept

<u>Now</u>,

<h3>#1</h3>

\sf :  \implies \: y =  {1x}^{2}  + 7x - 5

Here,

  • C = -5
  • I.e. y-intercept is -5

<h3>#2</h3>

\sf :  \implies \: y =  {1x}^{2}   - 3x  + 8

Here,

  • C = 8
  • I.e. y-intercept is 8

<h3>#3</h3>

\sf :  \implies \: y =  {1x}^{2}   - 15x  - 11

Here,

  • C = -11
  • I.e. y-intercept is -11
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A linear equation has maximum power of a variable(variables) 1.

In order to find the linear equations we need to check the equations with variable with power one.

Also the variable should be in numerator only.

Let us check option one by one:

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Therefore, it's not a linear equation.

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d-y = -2/3x + 4/3.

We have x and y powers only 1.

Therefore, it's the only linear equation.

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3 years ago
Evaluate each expression for the given value of the variable <br> x-3/10 for x=1/2
faltersainse [42]

x-3/10 for x=1/2

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4 years ago
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Naya [18.7K]
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4 years ago
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Willy has compounded monthly to invest his summer earnings of $4259 in the
pogonyaev

We have been given that Willy has compounded monthly to invest his summer earnings of $4259 in the  Rock Solid Bank. The bank is offering 6%. We are asked to find the amount of money will be after 5 years.

We will use compound interest formula to solve our given problem.

A=P(1+\frac{r}{n})^{nt}, where,

A = Final amount after t years,

P = Principal amount,

r = Annual interest rate in decimal form,

n = Number of times interest is compounded per year.

t = Time in years.

6\%=\frac{6}{100}=0.06

Since interest is compounded monthly, so n=12 and P=4259.

A=\$4259(1+\frac{0.06}{12})^{12\cdot 5}

A=\$4259(1+0.005)^{60}

A=\$4259(1.005)^{60}

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Therefore, Will will have approximately \$5744.75 in 5 years.

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