Are you doing FLVS? IF so I need hep
Answer:
Length of the field: 94 m
Width of the painting: 61 cm
Step-by-step explanation:
Use the perimeter formula, P = 2l + 2w, to find the length:
Plug in the perimeter and width into the equation:
P = 2l + 2w
336 = 2l + 2(74)
336 = 2l + 148
188 = 2l
94 = l
So, the length of the field is 94 m.
To find the width of the painting, use the area formula, A = lw
Plug in the area and length into the equation:
A = lw
5795 = 95w
61 = w
So, the width of the painting is 61 cm.
Length of the field: 94 m
Width of the painting: 61 cm
To round this we have to go to the thousands place since the thousands place in this question is 8 its closer to 10 so the answer is 10k or 10,000
Volume=(pi)(radius^2)(height)
Volume=(pi)(5^2)(12)
V=(pi)(25)(12)
V=(pi)(300)
Answer:
NO amount of hour passed between two consecutive times when the water in the tank is at its maximum height
Step-by-step explanation:
Given the water tank level modelled by the function h(t)=8cos(pi t /7)+11.5. At maximum height, the velocity of the water tank is zero
Velocity is the change in distance with respect to time.
V = {d(h(t)}/dt = -8π/7sin(πt/7)
At maximum height, -8π/7sin(πt/7) = 0
-Sin(πt/7) = 0
sin(πt/7) = 0
Taking the arcsin of both sides
arcsin(sin(πt/7)) = arcsin0
πt/7 = 0
t = 0
This shows that NO hour passed between two consecutive times when the water in the tank is at its maximum height
