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Svetach [21]
3 years ago
10

Zöe schedules advertising for a radio station. She must fill 12 minutes each hour with 30 second ads and 60 second ads. Zöe sold

twice as many 60 second ads as she did 30 second ads. She defines x as the number of 30 second ads and y as the number of 60 second ads that she sold. Zöe writes the system    and . Which statement identifies Zöe’s error and the correction that is needed?  Zöe used seconds to measure time for each ad, but she used minutes for the total. She should have used . Zöe set up an equation that would translate to “twice the number of 30 second ads = the number of 60 second ads.”  She should have used . Zöe compared the number of 30 second ads to the number of 60 second ads without  including the total number of ads. She should have used . Zöe did not include the whole hour in the total time. She should have used .
Mathematics
1 answer:
PilotLPTM [1.2K]3 years ago
8 0
I cannot see Zoe's work to explain the error, but the correct method of solving is listed:

x is the number of 30-second ads
y is the number of 60-second ads

x+y=12(60)=720 would be the first equation; this is because while the ads together make 12 minutes, the ad times are in seconds.  This means we must multiply 12 by 60.

y=2x is the second equation

Our system is then
x+y=720
y=2x

We will use substitution to solve this.  Plug 2x in place of y in the first equation:
x+2x = 720

Combine like terms:
3x = 720

Divide both sides by 3:
3x/3 = 720/3
x = 240

Substitute this value in for x in the second equation:
y=2(240)
y=480
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CaHeK987 [17]

Answer: Brielle will run the marathon faster.

Brielle = 104.8 minutes  

Joshua = 157.2 minutes

Step-by-step explanation:

Speed rate = distance /time

Brielle = 1.25 /10 = 0.125 miles per minute

Joshua = 1.5/18 = 0.083333 =1/12 miles per minute

Since 0.125 (Brielle) > 1/12 (Joshua)

Brielle will run the marathon faster.

To calculate the time that takes each one to run the entire race (13.1 miles)

Time= distance / speed

  • Brielle = 13.1 /0.125 = 104.8 minutes
  • Joshua = 13.1 / (1/12)= 157.2 minutes

Feel free to ask for more if needed or if you did not understand something.

8 0
3 years ago
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Makovka662 [10]

Answer:

Respuesta D

Step-by-step explanation:

Paola afirma: Todo número compuesto par, se puede escribir como la multiplicación de factores primos.

Esta afirmación es cierta, pues es un caso  de la afirmación de que todo número natural mayor que uno se puede escribir como multiplicación de números primos. A este proceso se le llama descomposición en factores primos.

Edwin afirma: Todo número compuesto impar se puede escribir como la suma de dos números primos.

Esta afirmación es falsa. Note que al sumar dos números impares de la forma 2k+1 y 2m+1 para k distinto de m, se obtiene

2k+1+2m+1 = 2(km+1)

Es decir, la suma de dos números impares es siempre par.

Note que a excepción de 2, todo número primo es impar. Para que esta afirmación fuera cierta, necesariamente tendría que pasar que cualquier número impar k se escriba de la forma p+2 donde p es un número primo. Esto es equivalente que para cualquier número impar k, el número k-2 sea primo.

Basta con dar un ejemplo para ver que esto no pasa. Tomemos k=11. En este caso, k-2 = 9, el cuál no es un número primo. Entonces 11 no se puede  descomponer como la suma de dos números primos.

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3 years ago
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Answer:

0 in²

Step-by-step explanation:

Maybe it would help to show some lines or something shape-like.

3 0
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