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enyata [817]
3 years ago
9

John checked his bank account and noticed that he had a balance of −$12.00. He immediately deposited $12.00 in his account. What

is the balance of his account after the $12.00 deposit? Drag and drop the label on the number line to show the balance on John’s account.
Mathematics
2 answers:
Elena-2011 [213]3 years ago
5 0

Answer:

$0

Step-by-step explanation:

<---*-12*------------0------------*12*--->

You start from negative twelve and add 12.

                                            count up 12 spaces

<---*-12*_-11_-10_-9_-8_-7_-6 _-5_-4_-3_-2 _-1 _0_1_2_3_4_5_6_7_8_9_10....

       ⬆

*start here*

<em>or if you understand it better like this...</em>

-12 + (1 x 12)

<em>or if you still cant wrap your brain around it...</em>

<em />

-12 + 12 = 0

<em>I don't know how you learn best so I put it in three ways :]</em>

<em></em>

<3 Enjoy,

    Dea

olga55 [171]3 years ago
5 0

Answer:

The answer should be 24

Step-by-step explanation:

He had 12 dollars in his account, and he added another 12 dollars. this leaves 24 dollars in total to his account

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denpristay [2]

Answer:

the left side of the line

Step-by-step explanation:

6 0
4 years ago
What is the value of x
motikmotik

Answer:

x = 4

Step-by-step explanation:

<u>All triangles add up to 180 degrees</u>

76 + 17x + 9x = 180

76 + 17x + 9x - 76 = 180 - 76

26x / 26 = 104 / 26

x = 4

Answer:  x = 4

3 0
3 years ago
Find the general solution of the differential equation and check the result by differentiation. (Use C for the constant of integ
atroni [7]

Answer: y=Ce^(^3^t^{^9}^)

Step-by-step explanation:

Beginning with the first differential equation:

\frac{dy}{dt} =27t^8y

This differential equation is denoted as a separable differential equation due to us having the ability to separate the variables. Divide both sides by 'y' to get:

\frac{1}{y} \frac{dy}{dt} =27t^8

Multiply both sides by 'dt' to get:

\frac{1}{y}dy =27t^8dt

Integrate both sides. Both sides will produce an integration constant, but I will merge them together into a single integration constant on the right side:

\int\limits {\frac{1}{y} } \, dy=\int\limits {27t^8} \, dt

ln(y)=27(\frac{1}{9} t^9)+C

ln(y)=3t^9+C

We want to cancel the natural log in order to isolate our function 'y'. We can do this by using 'e' since it is the inverse of the natural log:

e^l^n^(^y^)=e^(^3^t^{^9} ^+^C^)

y=e^(^3^t^{^9} ^+^C^)

We can take out the 'C' of the exponential using a rule of exponents. Addition in an exponent can be broken up into a product of their bases:

y=e^(^3^t^{^9}^)e^C

The term e^C is just another constant, so with impunity, I can absorb everything into a single constant:

y=Ce^(^3^t^{^9}^)

To check the answer by differentiation, you require the chain rule. Differentiating an exponential gives back the exponential, but you must multiply by the derivative of the inside. We get:

\frac{d}{dx} (y)=\frac{d}{dx}(Ce^(^3^t^{^9}^))

\frac{dy}{dx} =(Ce^(^3^t^{^9}^))*\frac{d}{dx}(3t^9)

\frac{dy}{dx} =(Ce^(^3^t^{^9}^))*27t^8

Now check if the derivative equals the right side of the original differential equation:

(Ce^(^3^t^{^9}^))*27t^8=27t^8*y(t)

Ce^(^3^t^{^9}^)*27t^8=27t^8*Ce^(^3^t^{^9}^)

QED

I unfortunately do not have enough room for your second question. It is the exact same type of differential equation as the one solved above. The only difference is the fractional exponent, which would make the problem slightly more involved. If you ask your second question again on a different problem, I'd be glad to help you solve it.

7 0
2 years ago
Write the equation of a line that passes through the points (4,6) and (−8,3)
kari74 [83]

Answer:

y= 1/4x+5

Step-by-step explanation:

y=mx+c

to calculate gradient: change in y/change in x

-3/-12 = 0.25

y = 1/4x+c

4 * 1/4 = 1

6-1 = 5

c= 5

Totally:
y= 1/4x+5

5 0
1 year ago
Please answer quickly!
Damm [24]

Answer:

2.57 or 2.5703939893007399

Hope this helped have a good one! :)

6 0
3 years ago
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