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2 years ago

Part A: What do the x-intercepts and maximum value of the graph represent in context of the described situation?

Mathematics

1 answer:

Klio2033 [76]2 years ago

8 0

The x intercept of the given graph of the company's profit is where the curve of the graph crosses the x-axis.

<h3>How to determine the x-intercept</h3>

From the figure, the graph crosses the x-axis at x values of 0 and 6

This represents the profit is 0 when the price is $0 and $6, respectively

<h3>The increasing and the decreasing interval</h3>

From the graph, the graph increases from x = 0 to x = x = 3, and it decreases from x = 3 to x = 6

These intervals represent when the profit increases, and when it decreases

<h3>The maximum value</h3>

This represents the maximum profit that can be made.

From the graph, the maximum profit is $120

<h3>The average rate of change</h3>

This is calculated as:

$m = \frac{f(b) - f(a)}{b - a}$

So, we have:

$m = \frac{f(3) - f(1)}{3 - 1}$

$m = \frac{f(3) - f(1)}{2}$

Substitute known values

$m = \frac{120 - 60}{2}$

$m = \frac{60}{2}$

Simplify

$m = 30$

Hence, the average rate of change from x = 1 to x = 3 is a profit of $30 per unit sale

Read more about functions and graphs at:

brainly.com/question/13473114

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Lostsunrise [7]

The answer is SAS

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2 years ago

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I will give you brainliest!!!! Which statement is true about the values x=3 and y=-1 ?

GenaCL600 [577]

Answer:

Step-by-step explanation:

6 0

2 years ago

At the beginning of the spelling bee there were 60 participants. One-third of the participants were eliminated during the first

lesya [120]

Participants = 60
.
First round:
1/3 of 60 = 20
or
60 x 1/3
= 60/3
= 20
60 - 20 = 40
There are 20 participants that are eliminated on the first sound and 40 participants to move on to the second sound.
.
Participants = 40
Second round:
1/4 of 40 = 10
or
40 x 1/4
= 40/4
= 10
40 - 10 = 30
There are 10 participants that are eliminated on the second round and 30 participants that is moving on to the next round.
.
Participants = 30
Third round:
1/6 of 30 = 5
or
30 x 1/6
= 30/6
= 5
30 - 5 = 25
There are 5 participants that are eliminated on the third round and 25 participants to move on to the fourth round.
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3 0

2 years ago

Which table represents a quadratic relationship?

svp [43]

In each case, the x-values are equally-spaced. Thus looking at second differences will tell you if the relation is quadratic. If the second differences are non-zero and constant, then the values have a quadratic relationship.

A. First differences are 2-4 = -2, 1-2 = -1, 0.5-1 = -0.5. Second differences are -1-(-2) = 1, -0.5-(-1) = 0.5. Since 1 ≠ 0.5, this relation is not quadratic. (It is exponential with a base of 1/2.)

B. First differences are 128-135 = -7, 105-128 = -23, 72-105 = -33. Second differences are -23-(-7) = -16, -33-(-23)=-10. Since -16 ≠ -10, this relation is not quadratic. (It is cubic, since 3rd differences are constant at +4.)

C. First differences are -23.2-(-23.4) = 0.2, -23.0-(-23.2) = 0.2, -22.8-(-23.0) = 0.2. Second differences are zero, so this is not a quadratic relation. (It is linear, with a slope of 0.2.)

D. First differences are 56-90 = -34, 26-56 = -30, 0-26 = -26. Second differences are -30-(-34) = 4, -26-(-30) = 4. These are constant (=4), so the relation is quadratic.

The appropriate choice is ...

... D. x -1 0 1 2 3 4

... f(x) 90 56 26 0 -22 -40

4 0

3 years ago

Read 2 more answers

The number of "destination weddings" has skyrocketed in recent years. For example, many couples are opting to have their wedding

Andru [333]

Answer:

There is no sufficient evidence to support the claim that wedding cost is less than $30000.

Step-by-step explanation:

Values (x) ∑(Xi-X)^2

----------------------------------

29.1 0.1702

28.5 1.0252

28.8 0.5077

29.4 0.0127

29.8 0.0827

30.1 0.3452

30.6 1.1827

----------------------------------------

236.1 3.4088

Mean = 236.1 / 8 = 29.51

$S_{x}=\sqrt{3.4088/(8-1)}=0.6978$

Statement of the null hypothesis:

H0: u ≥ 30 the mean wedding cost is not less than $30,000

H1: u < 30 the mean wedding cost is less than $30,000

Test Statistic:

$t=\frac{X-u}{S/\sqrt{n}}=\frac{29.51-30}{0.6978/\sqrt{8}}= \frac{-0.49}{0.2467}=-1.9861$

Test criteria:

SIgnificance level = 0.05

Degrees of freedom = df = n - 1 = 8 - 1 = 7

Reject null hypothesis (H0) if

$t$

Finding in the t distribution table α=0.05 with df=7, we have

$t_{0.05,7}=2.365$

$t>-t_{0.05,7}$ = -1.9861 > -2.365

Result: Fail to reject null hypothesis

Conclusion: Do no reject the null hypothesis

u ≥ 30 the mean wedding cost is not less than $30,000

There is no sufficient evidence to support the claim that wedding cost is less than $30000.

Hope this helps!

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3 years ago