From one vertex of an octagon you can draw 5 diagonals.
There are 8 vertices in an octagon, and we are choosing one as our starting vertex. There are then 7 vertices left to draw a line to, but 2 of the vertices are already connected to our main vertex (because they are connected along the side of the octagon). That leaves 5 vertices to draw a diagonal to from our original vertex.
Answer:
She need to walk 31/75 miles to school.
Step-by-step explanation:
It is given that,
Sofia has walk 
miles to school. She has already walk 
of a mile.
We need to find how much farther does she need to walk.
Total distance = 
Let she has to walk x distance to school.
Hence, she need to walk 31/75 miles to school.
Answer:
720 I think there is your answer from me
have a great day bye hop helps
Step-by-step explanation:
Answer:
3.
Step-by-step explanation:
Implicit differentiation:
x^2 y + (xy)^3 + 3x = 0
x^2 y + x^3y^3 + 3x = 0
Using the product rule:
2x* y + x^2*dy/dx + 3x^2 y^3 + x^3* (d(y^3)/dx) + 3 = 0
2xy + x^2 dy/dx + 3x^2 y^3 + x^3* 3y^2 dy/dx + 3 = 0
dy/dx(x^2 + 3y^2x^3) = (-2xy - 3x^2y^3 - 3)
dy/dx= (-2xy - 3x^2y^3 - 3) / (x^2 + 3y^2x^3)
At the point (-1, 3).
the derivative = (6 - 81 - 3)/(1 -27)
= -78/-26
= 3.
Answer:
x-4
Step-by-step explanation:
6x+6-5x-10=
x-4
( you have to multiply what is inside the parenthases to get to the first step that i did)
