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Elanso [62]
2 years ago
11

The questions on a test consist of 10 multiple choices, 3 essays, and 9 free responses. If the questions are ordered randomly, w

hat is the probability that the first question is a free response?
SAT
1 answer:
kiruha [24]2 years ago
7 0

Answer:

9/22 or 40.9%

Explanation:

Probability describes the likelihood of an event. To find simple probability, like in this question, use division.

To find the probability of the first question being a free response, you first need to find the total number of questions. This can be done by adding together all of the given information. There are 10 multiple choice, 3 essays, and 9 free responses.

  • 10 + 3 + 9 = 22

This means that there are 22 total questions. Next, find how many of these questions are free-response. We know that there are 9 free responses and 22 questions in total. So, 9 out of 22 are free responses. This can be rewritten as 9/22.

If you want to find the percentage, simplify the fraction and convert it to a percentage.

  • 9/22 = 0.409

Then, move the decimal 2 places to the right. This gives you 40.9%, which is the probability of the first question being a free-response.

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6 0
3 years ago
If you divide a number into 3 equal groups and then divide each group in half, you end up with 13. The starting number is.
Vlad [161]

Answer:

The starting number is 78.

Explanation:

(x / 3) / 2 = 13

divide a number by 3 (x / 3)

divide in half (x / 3) / 2

You get 13 (x / 3) / 2 = 13

Reverse the problem.

13 * 2 = 26

26 * 3 = 78

x = 78

Plug in the number.

(78 / 3) / 2 = 13

78 / 3 = 26

26 / 2 = 13

7 0
2 years ago
I NEED HELP!! 25 POINTS
laila [671]
Heat is the use of energy
8 0
3 years ago
Read 2 more answers
What are the coefficients for the binomial expansion of (a b)3? 1, 4, 6, 4, 1 1, 1 1, 2, 1 1, 3, 3, 1
Advocard [28]

The coefficients for the binomial expansion of (a + b)³ are 1, 3, 3, 1.

We have,

The binomial expansion (a + b)³,

So,

Now,

We know that,

Formula for binomial expansion,

i.e.

(u + v)ⁿ = ⁿC₀ · uⁿ · v⁰ + ⁿC₁ · uⁿ⁻¹ · v¹ + ⁿC₂ · uⁿ⁻² · v² + ⁿC₃ · uⁿ⁻³ · v³

Now,

According to the question,

Here,

u = a,

v = b,

And, n =3

Now,

Putting values,

i.e.

(a + b)³ = ³C₀ · a³ · b⁰ + ³C₁ · a³⁻¹ · b¹ + ³C₂ · a³⁻² · b² + ³C₃ · a³⁻³ · b³

We get,

(a + b)³ = ³C₀ · a³ · b⁰ + ³C₁ · a² · b¹ + ³C₂ · a¹ · b² + ³C₃ · a⁰ · b³

Now,

Using combination formula,

^{n} C_{r} = \frac{n!}{r!(n-r)!}

On solving we get,

(a + b)³ = a³ + 3 a² b + 3 a b² + b³

So,

Now,

The coefficients of :

a³ = 1,

3a²b = 3,

3ab² = 3,

b³ = 1,

So,

The coefficients of the given binomial expansion are 1, 3, 3, 1.

Hence we can say that the coefficients for the binomial expansion of (a + b)³ are 1, 3, 3, 1.

Learn more about binomial expansion here

brainly.com/question/3632340

#SPJ4

4 0
1 year ago
If a unit price label has a unit price of 21. 5 cents per pound, how much is the total price for an 8 pound package? a. $0. 37 b
jeka57 [31]

Answer:

b $1.72

Explanation:

21.5 cents for 1 pound

p for 8 pounds

p = 8 * 21.5

= 172 cents

= $172 / 100

= $1.72

6 0
2 years ago
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